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max2010maxim [7]

3 years ago

12

A 0.25 kg ideal harmonic oscillator has a total mechanical energy of 9.8 J. If the oscillation amplitude is 20.0 cm, what is the

oscillation frequency?a. 4.6 Hz b. 1.4 Hz c. 2.3 Hz d. 3.2 Hz

1 answer:

DanielleElmas [232]3 years ago

6 0

Answer:

7.04 Hz

Explanation:

x(t) = A cos(wt)

v(t) = - wA sin (wt)

Vmax = wA

E = 1/2 * m * (Vmax)^2

E = 1/2*m*(wA)^2

$w = \frac{1}{A} \sqrt{\frac{2E}{m} }$

f = w/ 2*pi

$f = \frac{1}{2*pi*A}*\sqrt{\frac{2E}{m} } \\f = \frac{1}{2 * pi * 0.2}*\sqrt{\frac{2(9.8)}{0.25} } \\f = 7.04 Hz$

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Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou

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Answer:

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Explanation:

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<h3>a. </h3>

The rotational speed is :

$2.7 \frac{m}{s^2} = \omega ^2 * 110 \ m$

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Knowing that there are $2\pi \ rad$ in a revolution and 60 seconds in a minute.

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<h3>b. </h3>

The rotational speed needed is :

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Knowing that there are $2\pi \ rad$ in a revolution and 60 seconds in a minute.

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