Answer:
3120J
Explanation:
Given parameters:
C = Specific heat capacity = 0.8J/g°C
Initial temperature = 20°C
Mass given = 5g
Final temperature = 800°C
Unknown:
Energy given to the mass = ?
Solution:
To find the energy given to the mass, let us simply use the expression below:
H = m c ΔT
H is the unknown, the energy supplied
m is the mass of the substance
c is the specific heat capacity
ΔT is the change in temperature
Input the variables;
H = 5 x 0.8 x (800 - 20) = 3120J
Answer:
A) ω = 6v/19L
B) K2/K1 = 3/19
Explanation:
Mr = Mass of rod
Mb = Mass of bullet = Mr/4
Ir = (1/3)(Mr)L²
Ib = MbRb²
Radius of rotation of bullet Rb = L/2
A) From conservation of angular momentum,
L1 = L2
(Mb)v(L/2) = (Ir+ Ib)ω2
Where Ir is moment of inertia of rod while Ib is moment of inertia of bullet.
(Mr/4)(vL/2) = [(1/3)(Mr)L² + (Mr/4)(L/2)²]ω2
(MrvL/8) = [((Mr)L²/3) + (MrL²/16)]ω2
Divide each term by Mr;
vL/8 = (L²/3 + L²/16)ω2
vL/8 = (19L²/48)ω2
Divide both sides by L to obtain;
v/8 = (19L/48)ω2
Thus;
ω2 = 48v/(19x8L) = 6v/19L
B) K1 = K1b + K1r
K1 = (1/2)(Mb)v² + Ir(w1²)
= (1/2)(Mr/4)v² + (1/3)(Mr)L²(0²)
= (1/8)(Mr)v²
K2 = (1/2)(Isys)(ω2²)
I(sys) is (Ir+ Ib). This gives us;
Isys = (19L²Mr/48)
K2 =(1/2)(19L²Mr/48)(6v/19L)²
= (1/2)(36v²Mr/(48x19)) = 3v²Mr/152
Thus, the ratio, K2/K1 =
[3v²Mr/152] / (1/8)(Mr)v² = 24/152 = 3/19
Answer:
19 N
Explanation:
From the question given above, the following data were obtained:
Pressure (P) = 1.9 kPa
Length (L) = 10 cm
Force (F) =?
Next, we shall convert 1.9 KPa to N/m². This can be obtained as follow:
1 KPa = 1000 N/m²
Therefore,
1.9 KPa = 1.9 KPa × 1000 N/m² / 1 KPa
1.9 KPa = 1900 N/m²
Thus, 1.9 KPa is equivalent to 1900 N/m².
Next, we shall convert 10 cm to m. This can be obtained as follow:
100 cm = 1 m
Therefore,
10 cm = 10 cm × 1 m / 100 cm
10 cm = 0.1 m
Thus, 10 cm is equivalent to 0.1 m
Next, we shall determine the area of the square. This can be obtained as follow:
Length (L) = 0.1 m
Area of square (A) =?
A = L²
A = 0.1²
A = 0.01 m²
Thus, the area of the square is 0.01 m².
Finally, we shall determine the force that must be exerted on the sensor in order for it to turn red. This can be obtained as follow:
Pressure (P) = 1900 N/m²
Area (A) = 0.01 m²
Force (F) =?
P = F/A
1900 = F / 0.01
Cross multiply
F = 1900 × 0.01
F = 19 N
Therefore, a force of 19 N must be exerted on the sensor in order for it to turn red.
Answer:
a) load in Newton is 96,138 b) 129.314mm
Explanation:
Stress = force/ area (cross sectional area of the bronze)
Force(load) = 294*10^6*327*10^-6 = 96138N
b) modulus e = stress/ strain
Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3
Strain = change in length/ original length = DL/ 129
Change in length DL = 129 * 2.34*10^ -3 = 0.31347
Maximum length = change in length + original length = 129.314mm
Answer:
In m/s^2:
a=11.3778 m/s^2
In units of g:
a=1.161 g
Explanation:
Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.
where:
v is the speed
r is the radius
Now,
In g units:
