Answer:
a. 5%
b. 55%
c. 70%
Step-by-step explanation:
a. The probability of customer wanting both services (P(O&T)) is:
![P(O)+P(T)+P(O\&T) = 0.75\\P(O)+P(O\&T) =0.60\\P(T)+P(O\&T) = 0.20\\P(O)+P(T)+P(O\&T) -[P(O)+P(T)+2P(O\&T)]=0.75 -(0.60-0.20)\\P(O\&T)=0.05=5\%](https://tex.z-dn.net/?f=P%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20%3D%200.75%5C%5CP%28O%29%2BP%28O%5C%26T%29%20%3D0.60%5C%5CP%28T%29%2BP%28O%5C%26T%29%20%3D%200.20%5C%5CP%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20-%5BP%28O%29%2BP%28T%29%2B2P%28O%5C%26T%29%5D%3D0.75%20-%280.60-0.20%29%5C%5CP%28O%5C%26T%29%3D0.05%3D5%5C%25)
The probability is 5%
b. The probability that the customer will need an oil change, but not a tire rotation (P(O)) is :

The probability is 55%
c. The probability that the customer will want exactly one of these two services (P(O)+P(T)) is:

The probability is 70%
The data is not linear. From (3, 1) to (7, 2), we add 4 to the x-value and add 1 to the y-value. This pattern continues for a little while, however, from (11, 3) to (18, 5), we add only 7 to the x-value even though we added 2 to the y-value. Given this information, we can determine that this is not linear data.
The median is 52, so the answer would be B.