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3 years ago

Solve for x. 5x - [3x + 4(x - 2)] = 9x - [4x + 5x + 10]

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

Answer:

x=9

Step-by-step explanation:

zavuch27 [327]3 years ago

6 0

Answer:

all work is shown and pictured

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Mel has 6 pens. Amir has 6 more pens than Mel. How many pens does Amir have?

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Step-by-step explanation:

6+6=12

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3 years ago

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Which point is located at (Negative 3.5, Negative 4.5)? 1 point A

Bumek [7]

Answer:

The answer A

Step-by-step explanation:

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3 years ago

Heres another math question! Please no links, and dont answer if you dont have an answer or I will report!

dsp73

The answer is subtract 5 from both sides :) by doing this, the equation becomes x= 7-5, isolating the variable (x) hope this helps!! <3

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3 years ago

100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).

victus00 [196]

Answer:

The value of $h^\prime(1)=5$

Step-by-step explanation:

Given that $h(x)=f(f(x))$

now to find $h(x)=f(f(x))$ from the given functions f(x) and f'x

let $h(x)=f(f(x))$

Then put x=1 in above function we get

$h(1)=f(f(1))$

$=f(3)$ (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

$h^{\prime}(x)=f^{\prime}(f^\prime(x))$ (since $h(x)=f(f(x))$ )

put x=1 in above function we get

$h^{\prime}(1)=f^{\prime}(f^\prime(1))$

$=f^{\prime}(2)$ (From the table $f^\prime(1)=2$ and $f^\prime(2)=5$ )

$h^{\prime}(1)=5$

Therefore $h^{\prime}(1)=5$

4 0

3 years ago

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A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i

lutik1710 [3]

Answer: $1-(\frac{364}{365})^n$

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^x$ , where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

$p=\dfrac{1}{365}$

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

$P(x\geq1)=1-P(x$

Hence, the probability there is at least one day in a year when nobody has a birthday = $1-(\frac{364}{365})^n$

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3 years ago