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kotegsom [21]
4 years ago
12

Bacteria that live around deep-sea, hot-water vents obtain energy by oxidizing inorganic hydrogen sulfide belched out by the ven

ts. They use this energy to build organic molecules from carbon obtained from the carbon dioxide in seawater. These bacteria are __________.
Chemistry
1 answer:
Ber [7]4 years ago
3 0

Answer:

Chemoautotrophs

Explanation:

Autotrophs are groups of organisms that are capable of manufacturing their own food (organic molecules) through the fixation of carbon dioxide. There are two types of autotrophs:

  • <em>Photoautotrophs fix carbon dioxide by using light as the energy for driving the process.</em>
  • <em> </em><em>Chemoautotrophs f</em><em>ix carbon dioxide by  using energy from the oxidation of inorganic molecules such as magnesium, or sulfur.</em>

Chemoautotrophs usually inhabit extreme environment such hot vents, deep sea, etc.

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erastovalidia [21]

C. the denser the plants the better.

Answer:

C

7 0
3 years ago
Read 2 more answers
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation:
nignag [31]

Answer:  1) Maximum mass of ammonia  198.57g  

2) The element that would be completely consumed is the N2

3) Mass that would keep unremained, is the one of  the excess Reactant, that means the H2 with 3,44g

Explanation:

  • In order to calculate the Mass of ammonia , we first check the Equation is actually Balance:

N2(g) + 3H2(g) ⟶2NH3(g)

Both equal amount of atoms side to side.

  • Now we verify which reagent is the limiting one by comparing the amount of product formed with each reactant, and the one with the lowest number is the limiting reactant. ( Keep in mind that we use the  molecular weight of 28.01 g/mol N2; 2.02 g/mol H2; 17.03g/mol NH3)

Moles of ammonia produced with 163.3g N2(g) ⟶ 163.3g N2(g) x (1mol N2(g)/ 28.01 g N2(g) )x (2 mol NH3(g) /1 mol N2(g)) = 11.66 mol NH3

Moles of ammonia produced with 38.77 g H2⟶  38.77 g H2 x ( 1mol H2/ 2.02 g H2 ) x (2 mol NH3 /3 mol H2 ) = 12.79 mol NH3

  • As we can see the amount of NH3 formed with the N2 is the lowest one , therefore the limiting reactant is the N2 that means, N2 is the element  that would be completey consumed, and the maximum mass of ammonia will be produced from it.
  • We proceed calculating the maximum mass of NH3 from the 163.3g of N2.

11.66  mol NH3 x (17.03 g NH3 /1mol NH3) = 198.57 g NH3

  • In order to estimate the mass of excess reagent, we start by calculating how much H2 reacts with the giving N2:

163.3g N2 x (1mol N2/28.01 g N2) x ( 3 mol H2 / 1 mol N2)x (2.02 g H2/ 1 mol H2) = 35.33 g H2

That means that only 35.33 g H2 will react with 163.3g N2 however we were giving 38.77g of  H2, thus, 38.77g - 35.33 g = 3.44g H2 is left

3 0
3 years ago
During a tug of war competition neither team was able to gain an advantage which of the following explains the force is this sit
natulia [17]

Answer:

b i did the test

Explanation:

8 0
3 years ago
Which best describes the relative positions of protons, neutrons, and electrons in an atom?
Anastaziya [24]
Hello!

The center of an atom is called the nucleus; it is comprised of protons and neutrons, collectively known as nucleons. The electrons float around the nucleus in a cloud.

Answer:
A) Protons and neutrons are in the center of the atom, and electrons move around in the cloud.
6 0
3 years ago
List of charge of elements that do not form compound easily​
adelina 88 [10]

Answer:

The highlighted words in the explanation.

Explanation:

A clue comes by considering the noble gas elements, the rightmost column of the periodic table. These elements—helium, neon, argon, krypton, xenon, and radon—do not form compounds very easily, which suggests that they are especially stable as lone atoms. What else do the noble gas elements have in common?

7 0
3 years ago
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