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statuscvo [17]
1 year ago
13

Changes in the composition of the atmosphere have caused gradual changes in earth's _______ throughout history, causing changes

in plant and animal life that contributed to mass extinctions.
Chemistry
1 answer:
bearhunter [10]1 year ago
6 0

climate

Changes in the composition of the atmosphere have caused gradual changes in earth's <u>climate</u> throughout history, causing changes in plant and animal life that contributed to mass extinctions.

The following are some of the reasons:

  • UV light
  • climate
  • pollutants
  • hydrofluorocarbons

heat

  • The surface of the Earth warms up as sunlight strikes it.
  • Surface-emitted infrared light is absorbed in the atmosphere and transformed into heat.
  • The temperature close to the surface rises as a result of this heat being trapped in the atmosphere.
<h3>UV light:</h3>
  • indirect impacts of climate change on UV radiation from the surface.
  • By changing the concentrations of ozone, UV-absorbing tropospheric gases, aerosols, and clouds in the atmosphere, climate change may have indirectly affected UV radiation levels in the past.
  • These influences are probably going to persist in the future.
<h3>climate:</h3>
  • People are at risk from food and water shortages, greater flooding, high heat, an increase in disease, and economic loss due to climate change.
  • Conflict and human migration are potential outcomes.
  • Climate change is the top hazard to world health in the twenty-first century, according to the World Health Organization (WHO).
<h3>pollutants:</h3>
  • these are also resulting in the increase of temperature of the Earth and is also damaging ozone layer.

To learn more about the changes in earth visit:

brainly.com/question/13434833?

#SPJ4

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Calculate 50g 25.0c to 95.000<br>O.897 J / (g.c)​
chubhunter [2.5K]

Answer:

Q = 3139.5 j

Explanation:

Given data:

Mass = 50 g

Initial temperature = 25°C

Final temperature = 95°C

Specific heat capacity = 0.897 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  95°C - 25°C

ΔT = 70°C

Q = m.c. ΔT

Q = 50 g× 0.897 J/g.°C ×70°C

Q = 3139.5 j

3 0
3 years ago
Calculate the cell potential, E, for the following reactions at 26.29 °C using the ion concentrations provided. Then, determine
yanalaym [24]

Answer:

I will work only one of the listed equations ... you follow the given example for the remaining reactions. Thank you :-)

Rxn 1: Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s)

a) E(Pt⁺²/Fe°) = - 1.668v

b) Process is Non-spontaneous if E(cell) < 0

Explanation:

Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s) ⇔

Pt°(s)|Pt⁺²[0.057M]║Fe⁺²[0.006M]|Fe°(s)

As written, Pt° is shown undergoing oxidation with Fe⁺² undergoing reduction. Applying the reduction potentials to the analytical equations for E(cell) and ΔG(cell) gives E(Pt/Fe⁺²) < 0 and ΔG(Pt/Fe⁺²) > 0 which indicate a non-spontaneous process. The following supports this conclusion.

E°(Fe⁺²) = -0.44v

E°(Pt⁺²) = +1.20v

E°(Pt/Fe⁺²) =E°(Redn) - E°(Oxidn) =E°(Fe⁺²) - E°(Pt⁺²)

= -0.44v - (+1.20v) = - 1.64v

[Fe⁺²] = 0.0066M

[Pt⁺²] = 0.057M

n = electrons transferred = 2

E(nonstd) = E°(std) - (0.0592/n)logQ);

Q = [Pt⁺²]/[Fe⁺²]

= -1.64v - (0.0592/2)log[0.057M]/[0.006M]v = -1.668v

Also, if ΔG(cell) > 0 => indicates non-spontaneous process

ΔG(Pt/Fe⁺²) = - nFE = -(2)(96,500Coulombs)((-1.664v) > 0 Kj => nonspontaneous rxn. (1 Coulomb-volt = 1 Kilojoule)

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german
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soldi70 [24.7K]

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As the temperature of a liquid increases, its viscosity decreases.
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