1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Airida [17]
4 years ago
8

What is the primary visible color of an emission nebula?

Physics
1 answer:
zzz [600]4 years ago
7 0
In emission nebulae, there are interstellar clouds of hydrogen, which glow red because of the intense radiation of hot stars inside the nebula
You might be interested in
David and Fiona want to know about how mass affects the motion of an object. David uses three objects with masses of 2 kg, 3 kg,
Natali [406]

Answer: the answer is D if its not i'm really sorry

8 0
2 years ago
A car with a mass of 1,400 kg is traveling at a speed of 40 m/s. What is its momentum?
adell [148]

Answer:

The answer is

<h2>56,000 kgm/s</h2>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

m = 1400 kg

v = 40 m/s

We have

momentum = 1400 × 40

We have the final answer as

<h3>56,000 kgm/s</h3>

Hope this helps you

7 0
3 years ago
Determine the current in the 7-ohm resistor for the circuit shown in the figure. Assume that the batteries are ideal and that al
seraphim [82]

Answer:

I₁ = 1.6 A (through 7 Ohm Resistor)

I₂ = 1.3 A (through 8 Ohm Resistor)

I₃ = I₁ - I₂ = 1.6 A - 1.3 A = 0.3 A (through 4 Ohm Resistor)

Explanation:

Here we consider two loops doe applying Kirchhoff's Voltage Law (KVL). The 1st loop is the left side one with a voltage source of 12 V and the 2nd Loop is the right side one with a voltage source of 9 V. We name the sources and resistor's as follows:

R₁ = 7 Ω

R₂ = 4 Ω

R₃ = 8 Ω

V₁ = 12 V

V₂ = 9 V

Now, we apply KVL to 1st Loop:

V₁ = I₁R₁ + (I₁ - I₂)R₂

12 = 7I₁ + (I₁ - I₂)(4)

12 = 7I₁ + 4I₁ - 4I₂

I₁ = (12 + 4 I₂)/11   ------------ equation (1)

Now, we apply KVL to 2nd Loop:

V₂ = (I₂ - I₁)R₂ + I₂R₃

9 = (I₂ - I₁)(4) + 8I₂

9 = 4I₂ - 4I₁ + 8I₂

9 = 12I₂ - 4I₁   -------------- equation (2)

using equation (1)

9 = 12I₂ - 4[(12 + 4 I₂)/11]

99 = 132 I₂ -  48 - 16 I₂

147 = 116 I₂

I₂ = 147/116

I₂ = 1.3 A

use this value in equation 2:

9 = 12(1.3 A) - 4I₁

4I₁ = 15.6 - 9

I₁ = 6.6 A/4

I₁ = 1.6 A

Hence, the currents through all resistors are:

<u>I₁ = 1.6 A (through 7 Ohm Resistor)</u>

<u>I₂ = 1.3 A (through 8 Ohm Resistor)</u>

<u>I₃ = I₁ - I₂ = 1.6 A - 1.3 A = 0.3 A (through 4 Ohm Resistor)</u>

4 0
3 years ago
Small pockets of synovial fluid that reduce friction and act as a shock absorber where ligaments and tendons rub against other t
Aloiza [94]

Answer:

bursae.

Explanation:

7 0
3 years ago
A(n) 1.3 kg mass sliding on a frictionless surface has a velocity of 7.1 m/s east when it undergoes a one-dimensional elastic co
Oxana [17]

Answer: 2.12 kg

Explanation:

Since the 1.3 kg object moves to the west after the collision, the other object will move to the east after the collision.

In an elastic collision, the relative velocity after the collision is the opposite of the relative velocity before the collision. Since the 1.3 kg object’s velocity before the collision is 6.7 m/s greater than the other object, after the collision, its velocity will be 6.7 m/s less than the other object. To determine the other object’s velocity, use the following equation.

v = 1.7 – 7.1 = -5.4 m/s

The negative sign means it is moving eastward. Let’s use this number is a momentum equation to determine its mass.

Initial momentum = 1.3 * 7.1 = 9.23 east

For the 1.3 object, final momentum = 1.3 * 1.7 = 2.21 west

To determine the final momentum of the other object, add these two numbers.

Final momentum = 11.44 east

To determine its mass, use the following equation.

m * 5.4 = 11.44

m = 11.44 ÷ 5.4 = 2.12 kg

To make sure that kinetic energy is conserved, let’s round this number to 2 kg and determine the final kinetic energies.

For the 1.3 object, KE = 1/2 * 1/3* 1.7^2 = 0.48

For the 2 kg object, KE = 1/2* 2 * 5.4^2 = 29.64

Total final KE = 29.64

Initial KE = 0.5* 1.3 * 7.1^2 = 32.77

Since I rounded the mass up to 2kg, this proves that kinetic energy is conserved and the mass is correct!

3 0
3 years ago
Other questions:
  • there are 1000 g in every kilogram of a box has a mass of 483 g what is the mass of the box in kilogram
    14·1 answer
  • What healthy snack can provide protein after physical activity?
    5·1 answer
  • Is fire actually hot and why do we call it hot; is it a classification for when something burns you.
    9·1 answer
  • What is the equivalent resistance between points A and B?
    6·1 answer
  • The wavelengths of light emitted by a firefly span the visible spectrum but have maximum intensity near 550 nm. A typical flash
    5·1 answer
  • Due to tides mean sea level off of Newport Beach reaches a height of 1.3 meters during high tide and 0.3 meters during low tide.
    12·1 answer
  • A student is given an assignment to demonstrate diffraction. He takes a photograph of a straw in a glass of water. The straw app
    15·2 answers
  • Use complete sentences to describe an extra-solar (exo) planet
    12·2 answers
  • Johanna is studying what happens to the energy as a ball rolls down a ramp. What is she studying? Check all that apply.
    8·1 answer
  • Which of the following statements accurately describes the atmospheric patterns that influence local weather?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!