Answer:
1367.7 g of ethylene glycol was added to the solution
Explanation:
In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm
ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')
525.8 mmHg - 451 mmHg = 451 mmHg . Xm
74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)
Xm = Mole fraction of solute / Moles of solute + Moles of solvent
We can determine the moles of solvent → 2000 g . 1 mol/18 g = 111.1 mol
(Notice we converted the 2kg of water to g)
0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent
0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute
18.4 moles = Moles of solute - 0.166 moles of solute
18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles
Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g
Diffusion is the process of a substance spreading out to evenly fill its container or environment. Kinetic energy of particles of matter increases with an increase in temperature. More the kinetic energy in the particles, more is the rate of diffusion. so diffusion is faster in the summer!
hope this helps!
Molarity is calculated by using following formula,
Molarity = Moles / Volume
Data Given:
Moles = 23 moles
Volume = 100 ml ÷ 1000 = 0.1 L
Putting values in eq. 1,
Molarity = 23 mol / 0.1 L
Molarity = 230 mol/dm³
Result:
When 23 mol of solute is dissolved in a solvent to make a solution of 100 ml, then it will have a Molarity of 230 mol/dm³.