Answer:
nvnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnv
Explanation:
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Answer:
nc
Explanation:
cjshdgcuidenuyeiydn7eydn8y8c
Answer:
The answer to your question is:
1.- 320 ml
2.- 0.63 M
Explanation:
Data
V = ? AlBr₃ = 0.157 M
mass = 13.4 g
Process
MW ALBr₃ = 27 + (80x3) = 267 g
267 g -------------------- 1 mol
13.4 g ------------------ x
x = (13.4 x 1) / 267
x = 0.05 moles
Volume = 0.05/ 0.157
= 0.320 l or 320 ml
2.-
NaNO₃ mass = 20.2 g
V = 375 ml
Molarity = ?
MW = 23 + 14 + 48 = 85g of NaNO₃
85 g of NaNO₃ ----------------- 1 mol
20.2 g ----------------- x
x = (20.2 x 1) / 85
x = 0.24 mol
Molarity = 0.24 / 0.375
= 0.63
