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natta225 [31]
3 years ago
12

A rigid layer that lies outside the cell’s membrane is

Physics
1 answer:
Thepotemich [5.8K]3 years ago
8 0
It’s a cell wall, but they are only in a plant cell.
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A conductor carrying a current I = 16.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A
Jet001 [13]

To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,

F = ILBsin \theta

Here,

I = Current

L = Length

B = Magnetic Field

\theta = Angle between Force and Magnetic Field

But \theta = 90\°

F = ILB

Rearranging to find the Magnetic Field,

B = \frac{F}{IL}

Here the force per unit length,

B = \frac{1}{I}\frac{F}{L}

Replacing with our values,

B = \frac{0.130N/m}{16.5}

B = 0.0078T

Therefore the magnitude of the magnetic field in the region through which the current passes is 0.0078T

6 0
3 years ago
How does the digestive system interact with the following organ systems (circulatory, muscular and nervous system) to maintain h
Lemur [1.5K]

Answer:

The circulatory system breaks down food and gets / absorbs nutrients. The muscular system works to get nutrients to the rest of the body. The nervous system basically controls the digestive system and sends information to the brain.

I'm pretty sure I'm right, but please correct me if I'm wrong! :)

5 0
3 years ago
A 3.45-kg centrifuge takes 100 s to spin up from rest to its final angular speed with constant angular acceleration. A point loc
Dafna11 [192]

Answer:

(a) 18.75 rad/s²

(b) 14920.78 rev

Explanation:

(a)

First we find the acceleration of the centrifuge using,

a = (v-u)/t......................... Equation 1

Where v = final velocity, u = initial velocity, t = time.

Given: v = 150 m/s,  u = 0 m/s ( from rest), t = 100 s

Substitute into equation 1

a = (150-0)/100

a = 1.5 m/s²

Secondly we calculate for the angular acceleration using

α = a/r..................... Equation 2

Where α = angular acceleration, r = radius of the centrifuge

Given: a = 1.5 m/s², r = 8 cm = 0.08 m

substitute into equation 2

α = 1.5/0.08

α = 18.75 rad/s²

(b)

Using,

Ф = (ω'+ω).t/2........................... Equation 3

Where Ф = number of revolution of the centrifuge, ω' = initial angular velocity, ω = Final angular velocity.

But,

ω = v/r and ω' = u/r

therefore,

Ф = (u/r+v/r).t/2

where u = 0 m/s (at rest),  = 150 m/s, r = 0.08 m, t = 100 s

Ф = [(0/0.08)+(150/0.08)].100/2

Ф = 93750 rad

If,

1 rad = 0.159155 rev,

Ф = (93750×0.159155) rev

Ф = 14920.78 rev

6 0
3 years ago
4. List 3 detailed examples that illustrate Newton's 2nd Law.
NNADVOKAT [17]

Examples of Newton's Second Law of Motion

Pushing a Car and a Truck. ...

Pushing a Shopping Cart. ...

Two People Walking Together. ...

Hitting a Ball. ...

Rocket Launch. ...

Car Crash. ...

Object thrown from a Height. ...

Karate Player Breaking Slab of Bricks.

3 0
2 years ago
If development does not occur in stages, then it is likely that development can be described as __________.
inna [77]

Answer:

I think it's D

ffjfjfjfjrjfjfjfjfj

5 0
3 years ago
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