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scoundrel [369]
3 years ago
14

A solid steel shaft is supported between 2 rigid supports; the diameter of AB is .625 in. and the diameter of BC is .75 in.

Engineering
2 answers:
Andreas93 [3]3 years ago
5 0

Answer:

The maximum allowable torque that can be applied at B without exceeding an allowable shear stress in the shaft of 10.0 ksi is 20.92 klb.in

Explanation:

The maximum torque will be equal to the torque on both ends A, and C, due to rods AB, and BC, respectively.

First we find polar moments of inertia of both rods:

(J)ab = π/2(0.625 in)^4

(J)ab = 0.2396 in^4

(J)bc = π/2(0.75 in)^4

(J)bc = 0.497 in^4

Now,

Tmax = (T)ab + (T)bc

Tmax = τ(J)ab/(r)ab + τ(J)bc/(r)cb

Tmax = (10000 psi)(0.2396 in^4)/(0.3125 in)  +  (10000 psi)(0.497 in^4)/(0.375 in)

Tmax = 7667.2 lb.in + 13253.33 lb.in

<u>Tmax = 20.92 klb.in</u>

ycow [4]3 years ago
5 0

I have attached the question with diagram for better understanding

Answer:

<u>T = 976 lb.in</u>

Explanation:

<h3>Please refer to the attached file below for detailed explanation. </h3><h3 />

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3 years ago
1)What are the three previous manufacturing revolutions Mr. Scalabre mentions? When did these take place?
Ostrovityanka [42]

The three previous manufacturing revolutions that Mr. Scalabre mentioned and their year of occurrence are:

  1. The steam engine in the mid-19th Century
  2. The mass-production model in the early 20th Century
  3. The first automation wave in the 1970s

<h3>What is a Manufacturing Revolution?</h3>

This refers to the process of change from a handicraft economy to industry production-based production.

Hence, we can see that Mr. Scalabre believes we are not growing in productivity because there has not been enough automation to perform the tasks needed.

The effect of robotics is making an impact on productivity because a lot of complex, difficult tasks are done by machines.

3D printing has made an impact on productivity because there is a reduction in the pressing cycle and errors due to negligence are reduced.

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8 0
2 years ago
A satellite orbits the Earth every 2 hours at an average distance from the Earth's centre of 8000km. (i) What is the average ang
AlexFokin [52]

Answer:

i)ω=3600 rad/s

ii)V=7059.44 m/s

iii)F=1245.8 N

Explanation:

i)

We know that angular speed given as

\omega =\dfrac{d\theta}{dt}

We know that for one revolution

θ=2π

Given that time t= 2 hr

So

ω=θ/t

ω=2π/2 = π rad/hr

ω=3600 rad/s

ii)

Average speed V

V=\sqrt{\dfrac{GM}{R}}

Where M is the mass of earth.

R is the distance

G is the constant.

Now by putting the values

V=\sqrt{\dfrac{GM}{R}}

V=\sqrt{\dfrac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{8000\times 10^3}}

V=7059.44 m/s

iii)

We know that centripetal fore given as

F=\dfrac{mV^2}{R}

Here given that m= 200 kg

R= 8000 km

so now by putting the values

F=\dfrac{mV^2}{R}

F=\dfrac{200\times 7059.44^2}{8000\times 10^3}

F=1245.8 N

3 0
3 years ago
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