All categories

2 years ago

A kitchen contains one section of counter that's 20 inches

Engineering

1 answer:

Ne4ueva [31]2 years ago

4 0

The number of receptacles that are needed for all of these kitchen areas are: C. Four.

<h3>What are receptacles?</h3>

Receptacles can be defined as types of sockets or series of outlets (openings) that provides a path where current can be taken in a wiring system, so as to run electrical appliances in buildings.

Based on the information provided, the number of receptacles that are needed for all of these kitchen areas are four because one would be used in each area.

Read more on receptacles here: brainly.com/question/23839796

#SPJ1

You might be interested in

Consider a very long rectangular fin attached to a flat surface such that the temperature at the end of the fin is essentially t

kodGreya [7K]

Answer:

$\frac{T-20}{130-20}= e^{-14.28*0.05}$

And if we solve for T we got:

$T= 20 + 110e^{-14.28*0.05} = 73.86 C$

The answer for this case would be $T = 73.86 C$ at 5cm from the base of the fin.

Explanation:

Data given

For this case we have the following data given:

$h = 20 \frac{W}{m^2 K}$ represent the heat transfer coefficient.

$p$ represent the perimeter for this case and would be given by:

$p = 2*0.05m +2*0.001m= 0.102m$

$k = 200 \frac{W}{m C}$ represent the thermal conductivity

$w = 5cm =0.05 m$ represent the width

$h = 1mm =0.001m$ represent the thickness

$A= wh= 0.05m *0.001m = 0.00005 m^2$

Solution to the problem

For this case we assume that we have steady conditions, the temperature of the fins varies just in one direction, the heat transfer coefficient not changes with the time and the thermal properties of the fin not change.

We can determine the temperature if the fin at x=5 cm=0.05 m from the base with the following formula:

$\frac{T-T_{\infty}}{T_b -T_{\infty}} = e^{-mx}$

Where m is a coefficient given by:

$m = \sqrt{\frac{hp}{kA}}=\sqrt{\frac{20 W/m^2 C 0.102 m}{200 W/ mC 0.00005 m^2}}= 14.28 m^{-1}$

The value of x for this case represent the distance $x =5 cm =0.05m$

$T_b =130 C$ represent the base temperature

$T_{\infty}= 20$ represent the temperature of the sorroundings or the ambient.

If we replace we have this:

$\frac{T-20}{130-20}= e^{-14.28*0.05}$

And if we solve for T we got:

$T= 20 + 110e^{-14.28*0.05} = 73.86 C$

The answer for this case would be $T = 73.86 C$ at 5cm from the base of the fin.

3 0

3 years ago

Which of the following statements are true about staying safe while

Tatiana [17]

Answer:

What you should do changes based on the hazards you're exposed to.

You should be aware of any hazards that are present.

3 0

3 years ago

The velocity components expressed in m/s<br>

olchik [2.2K]

The scalar absolute value (magnitude) of velocity is called speed, being a coherent derived unit whose quantity is measured in the SI (metric system) as metres per second (m/s or m⋅s−1). For example, "5 metres per second" is a scalar, whereas "5 metres per second east" is a vector.

3 0

3 years ago

What parts are needed to complete a loop for an LED?

nika2105 [10]

Answer:

it depends on what LED's your using... if you have one long strip of them you cant make a loop unless you want it to be bent

Explanation:

3 0

3 years ago

Read 2 more answers

At steady state, a cycle develops a power output of 10 kW for heat addition at a rate of 10 kJ per cycle of operation from a sou

aleksandr82 [10.1K]

Answer:

Number of cycle per minute = 75

Explanation:

given data

Power output Wnet = 10 KW

Temperature of hot reservoir = 1500 K

Temperature of cold reservoir = 300 K

solution

we know that Efficiency is express as

n = 1 - To ÷ Tk ...............1

here Tk is Temperature of hot reservoir and To is Temperature of cold reservoir

so put here value in equation 1 we get

n = 1- 300 ÷ 1500

n = 0.8

and Rate of heat input will be

Rate of heat input Qin = 10 × No. of cycles per sec

Rate of heat input Qin = 10 n

and

n = Wnet ÷ 10 n .......................2

put here value

0.8 = 10 ÷ 10 n

solve it we get

n = 1.25

so here Number of cycle per second is = 1.25

and Number of cycle per minute will be = 1.25 × 60

Number of cycle per minute = 75

6 0

4 years ago