Hi there!
According to Newton's Second Law, force is calculated with the formula:
F = m × a, where:
F = force (N)
m = mass (kg)
a = acceleration (m/s²)
Answer: 1.8
Explanation:
You are given
the object distance U = 24.8 cm
Focal length F = 16.0 cm
First find the image distance by using the formula:
1/f = 1/u + 1/v
Where V = image distance
Substitute u and f into the formula
1/16 = 1/24.8 + 1/v
1/ v = 1/16 - 1/24.8
1/v = 0.0625 - 0.04032258
1/v = 0.022177
Reciprocate both sides by dividing both sides by one
V = 45.09 cm
Magnification M is the ratio of image distance to the object distance. That is,
M = V/U
Substitute V and U into the formula
M = 45.09/24.8
M = 1.818
Magnification of the image is therefore equal to 1.8 approximately
Answer:
C. Quadruple
Explanation:
¨Drivers who are talking on the phone, even on a hands-free device, are up to four times more likely to be involved in a crash.¨
I hope this helps! Have a great day!
Answer:
53.13 °
Explanation:
In order to do this, we just need to apply the following:
tanα = Dy/Dx
Where:
Vy: speed of the ball in the y axis.
Vx: speed of the ball in the x axis.
At this point we do not need the speed of the first ball after the collision because in that moment is already heading in the direction that we are looking for. Therefore, we just need to use the innitial data to calculate the direction which the first ball will go.
According to this, then:
tanα = (40/30)
tanα = 1.3333
α = tan⁻¹(1.3333)
<h2>
α = 53.13°</h2>
This means that the final direction of the first ball is 53.13° and in the x axis because the starting momentum of this ball in the x axis has not dissapeared.
Hope this helps
Answer: The degree of the first term.
Explanation:
The function:
The left and right ends would be indicated when x is changed to -x. When this is substituted, the change is indicated by the first term because only the degree of first term is odd.
Let the left hand side be donated by -x.
Then,
Hence, the correct option is the degree of the first term indicates the left and right end points of the function.
