3 years ago

What happens to the momentum of an object when velocity is kept the same and the mass is increased?

Physics

1 answer:

Jet001 [13]3 years ago

6 0

Momentum = mass x velocity so if velocity is kept same and mass is increased then momentum will increase.

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Which has the greatest frictional force among this surfaces

fomenos

Answer:

D.sandy floor

Explanation:

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7 0

3 years ago

a man of mass 50 kg climbs up stairs each of height 0.2 m in 20 seconds .calculate the power of the man

Delicious77 [7]

How many stairs?
You can use this to find the work
U
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4 0

3 years ago

Two satellites A and B orbit the Earth in the same plane. Their masses are 5 m and 7 m, respectively, and their radii 4 r and 7

Dmitry [639]

Answer:

The ratio of their orbital speeds are 5:4.

Explanation:

Given that,

Mass of A = 5 m

Mass of B = 7 m

Radius of A = 4 r

Radius of B = 7 r

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$v_{A}=\sqrt{\dfrac{GM_{A}}{R_{A}}}$ ......(I)

The orbital speed of satellite B,

$v_{B}=\sqrt{\dfrac{GM_{B}}{R_{B}}}$ ......(I)

We need to calculate the ratio of their orbital speeds

Using equation (I) and (II)

$\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{\dfrac{GM_{A}}{R_{A}}}{\dfrac{GM_{B}}{R_{B}}}}$

Put the value into the formula

$\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{G\times5m\times7r}{G\times7m\times4r}}$

$\dfrac{v_{A}}{v_{B}}=\dfrac{5}{4}$

Hence, The ratio of their orbital speeds are 5:4.

8 0

3 years ago

Look at the divisions between 2 and 4. What level of precision does this stopwatch have based on the divisions marked on its fac

klemol [59]

Answer:

10ths of a second

Explanation:

Because I just did it

8 0

3 years ago

Later, while taking your groceries back to the car, you accidentally let go of your cart. It rolls straight down a grassy slope

VladimirAG [237]

Car is moving on the glassy slope with constant speed

Now we know that

$a = \frac{dv}{dt}$

so acceleration is rate of change in velocity

as we know that velocity is constant here so acceleration is zero

so here

$a = 0$

now as we know by Newton's II law

$F = ma$

since a = 0

$F = 0$

so net force will be ZERO on it during this motion

6 0

3 years ago