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Papessa [141]
3 years ago
9

After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

p. This is an excellent example of static charge built up by
A) conduction.
B) convection.
C) friction.
D) induction.
Physics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer: The correct answer is D.

Explanation:

Conduction: It is a process in which there is a transfer of energy directly.

Convection: It is a process in which there is a actual movement of the particle. Here, the motion of the matter takes place.

Friction: It opposes the motion of the object. It is directed in an opposite direction of the motion.

Induction: It is the process in which uncharged object is brought to near by the charged object then the charges will get induced in the uncharged object without touching it.

In the given problem, After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand up.

Therefore, induction is an excellent example of static charge.

Amanda [17]3 years ago
6 0

The answer is D) induction.

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Find the frequency of a wave of wavelength 2.5m and speed 400 m/s
Sedaia [141]

Answer:

The frequency of wave is 160Hz.

Explanation:

Given that the formula of speed is V = f×λ where V represents speed, f is frequency and λ is wavelength.

So first thing, you have to make frequency the subject by dividing wavelength on both sides :

v = f \times λ \:

v \div  λ =  f \times λ \div λ

f =  \frac{v}{λ}

Next you have to substitute the value of v and f into the formula :

Let λ = 2.5m,

Let v = 400m/s,

f =  \frac{400}{2.5}

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7 0
3 years ago
Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass
Gala2k [10]

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

\Delta W = \Delta PE + \Delta KE

Where,

PE = Potential Energy

KE = Kinetic Energy

\Delta W = (\Delta m)gh+\frac{1}{2}(\Delta m)v^2

Where,

m = Mass

g = Gravitational energy

h = Height

v = Velocity

Considering power as the change of energy as a function of time we will then have to

P = \frac{\Delta W}{\Delta t}

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

The rate of mass flow is,

\frac{\Delta m}{\Delta t} = \rho_w Av

Where,

\rho_w = Density of water

A = Area of the hose \rightarrow A=\pi r^2

The given radius is 0.83cm or 0.83 * 10^{-2}m, so the Area would be

A = \pi (0.83*10^{-2})^2

A = 0.0002164m^2

We have then that,

\frac{\Delta m}{\Delta t} = \rho_w Av

\frac{\Delta m}{\Delta t} = (1000)(0.0002164)(5.4)

\frac{\Delta m}{\Delta t} = 1.16856kg/s

Final the power of the pump would be,

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

P = (1.16856)((9.8)(3.5)+\frac{1}{2}5.4^2)

P = 57.1192W

Therefore the power of the pump is 57.11W

6 0
3 years ago
A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 563 K, and r
Schach [20]

Answer:

1.85 J/K

Explanation:

The computation of total change in entropy is shown below:-

Change in Entropy = Sum Q ÷ T

= \frac{-heat\ entering\ the\ reservoir}{Reservoir\ 1\ Temperature} + \frac{Conduction\ of\ heat}{Reservoir\ 2\ Temperature}

= \frac{-1760}{563} + \frac{1760}{354}

= -3.12 + 4.97

= 1.85 J/K

Therefore for computing the total change in entropy we simply applied the above formula.

As we can see that there is heat entering the reservoir so it will be negative while cold reservoir will be positive else the process would be impossible.

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3 years ago
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Alex_Xolod [135]

Answer:

sum of all forces on the air plane must be ZERO

So both forces must be of same magnitude

Explanation:

As we know that airplane is moving with uniform speed is horizontal plane is a straight line

so the motion of the air plane is uniform without any acceleration

So we will have

a = 0

acceleration must be zero

now by Newton's law

F_{net} = 0

F_1 + F_2 = 0

so sum of all forces on the air plane must be ZERO

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2 years ago
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