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Papessa [141]
3 years ago
9

After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

p. This is an excellent example of static charge built up by
A) conduction.
B) convection.
C) friction.
D) induction.
Physics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer: The correct answer is D.

Explanation:

Conduction: It is a process in which there is a transfer of energy directly.

Convection: It is a process in which there is a actual movement of the particle. Here, the motion of the matter takes place.

Friction: It opposes the motion of the object. It is directed in an opposite direction of the motion.

Induction: It is the process in which uncharged object is brought to near by the charged object then the charges will get induced in the uncharged object without touching it.

In the given problem, After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand up.

Therefore, induction is an excellent example of static charge.

Amanda [17]3 years ago
6 0

The answer is D) induction.

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<u>Explanation</u>:

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\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}

  • The angle between the two vectors is 90° .

\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}

  1. The dot product of two vectors .
  2. The cross product of two vectors .

\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}

⚡ Let \rm{\vec{a}} and \rm{\vec{b}} are the two vectors .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}

Where,

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\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}

  • cos 90° = <u>0</u>

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}

\rm{\red{\therefore}} [1] The dot product of two vectors is “ <u>0</u> ” .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}

  • sin 90° = <u>1</u>

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}

\rm{\red{\therefore}} [2] The cross product of two vectors is “ <u>ab</u> ” .

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