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Papessa [141]
3 years ago
9

After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

p. This is an excellent example of static charge built up by
A) conduction.
B) convection.
C) friction.
D) induction.
Physics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer: The correct answer is D.

Explanation:

Conduction: It is a process in which there is a transfer of energy directly.

Convection: It is a process in which there is a actual movement of the particle. Here, the motion of the matter takes place.

Friction: It opposes the motion of the object. It is directed in an opposite direction of the motion.

Induction: It is the process in which uncharged object is brought to near by the charged object then the charges will get induced in the uncharged object without touching it.

In the given problem, After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand up.

Therefore, induction is an excellent example of static charge.

Amanda [17]3 years ago
6 0

The answer is D) induction.

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2 hrs 45 minutes

Explanation:

You have to minus one hr because of tome change

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A professor designing a class demonstration connects a parallel-plate capacitor to a battery, so that the potential difference b
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Answer:

a)  Q = 397.57 pC , Q = 3.18 104 pC , b) C = 1.157 10⁻¹⁰ F ,  V = 3.4375 V ,

c)  U = 54.7 nJ ,  d) ΔU = 54 nJ,

Explanation:

a) The capacity of a capacitor is defined

        C = Q / V

        Q = C V

         

can also be calculated using geometry consideration

        C = e or A / d

         

we reduce to the SI system

       A = 25.0 cm² (1 m / 10² cm) 2 = 25.0 10⁻⁴ m²

       d = 1.53 cm = 1.53 10⁻² m

we substitute

         Q = eo A / d V

         Q = 8.85 10⁻¹² 25 10⁻⁴ / 1.53 10⁻² 275

         Q = 3.9757 10⁻¹⁰ C

         

let's reduce to pC

         Q = 3.9757 10⁻¹⁰ C (10¹² pC / 1 C)

          Q = 397.57 pC

when the capacitor is introduced into the water the dielectric constant is different

           Q = k Q₀

           Q = 80 397.57

           Q = 3.18 104 pC

b) Find capacitance and voltage after submerged in water

           C = k C₀

           C = 80 8.85 10⁻¹² 25 10⁻⁴ / 1.53 10⁻²

           C = 1.157 10⁻¹⁰ F

           V = Vo / k

            V = 275/80

            V = 3.4375 V

c) The stored energy is

             U = ½ C V²

              U = ½, 85 10⁻¹² 25 10⁻⁴ / 1.53 10⁻²     275²

             U = 5.47 10⁻⁸ J

let's reduce to nJ

              109 nJ = 1 J

               U = 54.7 nJ

d) energy after submerging

             U = ½ (kCo) (Vo / k) 2

             U = ½ Co Vo2 / k

             U = U₀ / k

             U = 54.7 / 80 nJ

              U = 0.68375 nJ

the energy change is

         ΔU = U₀ -U

          ΔU = 54.7 - 0.687375

           

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As you learned in Part B, a non-burning helium core surrounded by a shell of hydrogen-burning gas characterizes the subgiant sta
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Answer:

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F- The surface of the star becomes brighter and cooler

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D- The star's non burning helium core starts to contract and heat up

B- Pressure in the star's core decreases (EARLIEST STAGE)

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Answer:

The correct answer to the question is

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Explanation:

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m₂ = mass of second object

r = the distance between both objects

If the mass of one object remains unchanged while the distance to the second object and the second object’s mass are both doubled, we have

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Answer:

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Explanation:

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