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Papessa [141]
2 years ago
9

After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

p. This is an excellent example of static charge built up by
A) conduction.
B) convection.
C) friction.
D) induction.
Physics
2 answers:
Hitman42 [59]2 years ago
7 0

Answer: The correct answer is D.

Explanation:

Conduction: It is a process in which there is a transfer of energy directly.

Convection: It is a process in which there is a actual movement of the particle. Here, the motion of the matter takes place.

Friction: It opposes the motion of the object. It is directed in an opposite direction of the motion.

Induction: It is the process in which uncharged object is brought to near by the charged object then the charges will get induced in the uncharged object without touching it.

In the given problem, After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand up.

Therefore, induction is an excellent example of static charge.

Amanda [17]2 years ago
6 0

The answer is D) induction.

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A rope passes over a fixed sheave with both ends hanging straight down. The coefficient of friction between the rope and sheave
Oliga [24]

Answer:3.51

Explanation:

Given

Coefficient of Friction \mu =0.4

Consider a small element at an angle \theta having an angle of d\theta

Normal Force=T\times \frac{d\theta }{2}+(T+dT)\cdot \frac{d\theta }{2}

N=T\cdot d\theta

Friction f=\mu \times Normal\ Reaction

f=\mu \cdot N

and T+dT-T=f=\mu Td\theta

dT=\mu Td\theta

\frac{dT}{T}=\mu d\theta

\int_{T_2}^{T_1}\frac{dT}{T}=\int_{0}^{\pi }\mu d\theta

\frac{T_2}{T_1}=e^{\mu \pi}

\frac{T_2}{T_1}=e^{0.4\times \pi }

\frac{T_2}{T_1}==e^{1.256}

\frac{T_2}{T_1}=3.51

7 0
3 years ago
A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant a
RideAnS [48]

Answer:

-414.96 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2

F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N

The force the ground exerts on the parachutist is -414.96 N

If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase

5 0
3 years ago
2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

so the average velocity is

v=\frac{15 km}{2.0 h}=7.5 km/h

and the direction is the same as the displacement (east).

We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

t = 2.0 h * 3600 s/h = 7200 s

v=\frac{15,000 m}{7200 s}=2.1 m/s

4 0
3 years ago
Read 2 more answers
You are on a Parkour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long wal
makvit [3.9K]

Average speed = (total distance covered) / (time to cover the distance)

Total distance covered = (9.5m + 3.5m + 15m) = 28 meters

Time to cover the distance = 43 seconds

Average speed = (28 meters) / (43 seconds)

Average speed = 0.65 meters/second

4 0
3 years ago
2. A 1750 kg car accelerates at a rate of 4.0 m/s2. How much force is the cars engine producing?
8090 [49]

Answer:

<h2>7000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1750 × 4

We have the final answer as

<h3>7000 N</h3>

Hope this helps you

6 0
3 years ago
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