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snow_lady [41]
3 years ago
7

Introductory Astronomy1. Light is absorbed and emitted in the form ofwhich are "packets" ofelectromagnetic radiation that carry

a specific amount of energy.photonsionsexcited atomsprotons2. Light is characterized by which two properties? point)electromagnetic energy and wavelengthwavelength and frequencyfrequency and radiationOelectromagnetic radiation and gamma rays

Physics
1 answer:
k0ka [10]3 years ago
4 0
Light ... and all other forms of electromagnetic radiation ... behaves
as if it were a stream of 'packets' that we call 'photons', each one
carrying a specific amount of energy.

Light  ... and all other forms of electromagnetic radiation ... is
characterized by its wavelength.  That is, once you state its wavelength,
you've stated everything there is to know about the light, including its
frequency, and the energy carried by each photon. 
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6 0
3 years ago
The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
2 years ago
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tangare [24]

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Answer:

The correct answer is - option C. G.

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The overall energy of the reaction, including or excluding activation energy depends on the nature of the reaction if it is exothermic or endothermic. and products are represented by the G which shows the difference between the energy of the reactants and products.

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Explanation:

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