Answer:
The correct option is a
Explanation:
This question seeks to test a general rule in physics (on charges) which states that <u>like charges repel but unlike charges attract</u>. This means that, a negatively charged substance will repel or not attract another negatively charged material and the same applies to a positively charged substance also. However, a <u>negatively charged substance will attract a positively charged material and vice versa,</u> hence only a negatively charged rod will attract a positively charged hanging ball.
The sign of the charged particle is positively charged.
<h3>What is potential difference?</h3>
- When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
- There is potential energy stored in this charge that could flow when work is done on it.
- Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
- Here, voltage can be the potential differences.
The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.
Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.
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Answer:
3.222 ohms
Explanation:
If the total wire had a resistance of 29 ohms, when cut in three, each piece will have a resistance of 9.666 ohms.
As these three pieces (R1, R2 and R3) are now connected in parallel, the equivalent resistance R can be calculated using this equation:
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/9.666 + 1/9.666 + 1/9.666
1/R = 3/9.666
R = 9.666/3 = 3.222 ohms
The resistance between A and B will be 3.222 ohms
The frequency of the other wave is 613 Hz or 607 Hz.
The difference between the frequencies of two waves is called the beat frequency.
Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.
Which has a higher frequency is not mentioned. Therefore, there are two possibilities.
Δf = | 610 - 613 | = 3
or
Δf = | 610 - 607 | = 3
Therefore, the frequency of the other wave is 613 Hz or 607 Hz.
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