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Oksi-84 [34.3K]
2 years ago
11

How do I solve for this?

Physics
1 answer:
vova2212 [387]2 years ago
7 0
I can’t see anything
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A cruise ship travels directly toward the dock at a speed of 12 m/s
Hatshy [7]

Thanks for sharing that information.  After extensive calculation,
we can say with assurance that after some number of seconds,
a loud "crunch" is perceived by the souls aboard the ill-fated vessel.

3 0
3 years ago
What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

UAC   CUG   AGG   AUC

5 0
3 years ago
Tell me about your favorite science experiment. Give me a detailed account of the experiment and what you like about it.​
Aleks [24]

Answer:

nngh have

bjruh hjrhhj be rnrnnrnrnnnrnjrjnnnnnnnnrnrn n n and I was nrn

Explanation:

jbbbbbhhhjjnnnnnnnnnnjhvcc

Explanation:

5 0
3 years ago
One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction
Sophie [7]

Answer:

F = 156.3 N

Explanation:

Let's start with the top block, apply Newton's second law

         F - fr = 0

         F = fr

         fr = 52.1 N

Now we can work  with the bottom block

In this case we have two friction forces, one between the two blocks and the other between the block and the surface. In the exercise, indicate that the two friction coefficients are equal

we apply Newton's second law

Y axis

        N - W₁ -W₂ = 0

        N = W₁ + W₂

as the two blocks are identical

        N = 2W

X axis

        F - fr₁ - fr₂ = 0

        F = fr₁ + fr₂

indicates that the lower block is moving below block 1, therefore the upper friction force is

          fr₁ = 52.1 N

          fr₁ = μ N

a

s the normal in the lower block of twice the friction force is

          fr₂ = μ 2N

          fr₂ = 2 μ N

          fr₂ = 2 fr₁

we substitute

          F = fr₁ + 2 fr₁

          F = 3 fr₁

          F = 3  52.1

          F = 156.3 N

7 0
3 years ago
You discover a binary star system in which one member is a 15 solar mass main-sequence star and the other star is a 10 solar mas
Sever21 [200]

Answer:

A star with 15 solar masses is too big to be a main-sequence star.

4 0
3 years ago
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