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LekaFEV [45]
3 years ago
9

The plates of a parallel-plate capacitor each have an area of 0.1 m^2 and are separated by a 0.9 mm thick layer of porcelain. Th

e capacitor is connected to a 14 V battery. (The dielectric constant for porcelain is 7.) (a) Find the capacitance. (b) Find the charge stored. (c) Find the electric field between the plates.
Physics
1 answer:
podryga [215]3 years ago
4 0

Answer: a) 6.88 nF; b) 96 .32 nC; c) 108.83 * 10^3 N/C

Explanation: In order to solve this problem we need to used the expresion for the capacitor of two parallel plates, which is given by:

C=εo*A/d;  A is the area and d the separaction between the plates.

inside the capacitor there is a porcelain layer so we have to multiply by the dielectric constant (k=7).

Then C=8.85*10^-12*7*0.1 /0.0009=6.88 nF

Also we know that ΔV=Q/C

Q= C*ΔV= 6.88 nF* 14 V= 96 .32 nC

Finally, The electric field between the plates is given by:

E= σ/εo= Q/(A*εo)= 96.32 /(0.1*8,85* 10^-12)= 108.83 * 10^3 N/C

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Answer:

a = 1.152s

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c = 7.29m/s

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0 = 4-9.8(t)

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t = 4/9.8

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From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

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Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

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t =√0.554

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V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

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b = 0.817 m

c = 7.29m/s

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