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LekaFEV [45]
3 years ago
9

The plates of a parallel-plate capacitor each have an area of 0.1 m^2 and are separated by a 0.9 mm thick layer of porcelain. Th

e capacitor is connected to a 14 V battery. (The dielectric constant for porcelain is 7.) (a) Find the capacitance. (b) Find the charge stored. (c) Find the electric field between the plates.
Physics
1 answer:
podryga [215]3 years ago
4 0

Answer: a) 6.88 nF; b) 96 .32 nC; c) 108.83 * 10^3 N/C

Explanation: In order to solve this problem we need to used the expresion for the capacitor of two parallel plates, which is given by:

C=εo*A/d;  A is the area and d the separaction between the plates.

inside the capacitor there is a porcelain layer so we have to multiply by the dielectric constant (k=7).

Then C=8.85*10^-12*7*0.1 /0.0009=6.88 nF

Also we know that ΔV=Q/C

Q= C*ΔV= 6.88 nF* 14 V= 96 .32 nC

Finally, The electric field between the plates is given by:

E= σ/εo= Q/(A*εo)= 96.32 /(0.1*8,85* 10^-12)= 108.83 * 10^3 N/C

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A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes

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S = 5.508 × 10¹¹m

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