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Dahasolnce [82]
3 years ago
15

Sound waves that enter the external acoustic meatus eventually encounter the __________, which then vibrates at the same frequen

cy as the sound waves hitting it.
Physics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

tympanic membrane (eardrum)

Explanation:

The sound waves spread through the air and reach the outer ear, into which they penetrate through the ear canal. In doing so, they stimulate the eardrum, which closes the inner end of the duct. By vibrating this membrane, the vibration of a chain of ossicles located in the middle ear is induced. These ossicles transmit their vibration to the oval window, which is a membranous structure that communicates the middle ear with the cochlea of ​​the inner ear. When the oval membrane moves, it moves the liquid (perilymph) that fills one of the three cavities of the cochlea generating waves in it. These waves mechanically stimulate the sensory cells (hair cells) located in the organ of Corti, within the cochlea in the central cavity, the middle ramp. This cavity is filled with a liquid rich in K +, endolymph. The cells embedded in the endolymph, change their permeability to K + due to the movement of the cilia and respond by releasing a neurotransmitter that excites the nerve terminals, which initiate the auditory sensory pathway.

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A paper-filled capacitor is charged to a potential difference of V0=2.5 V. The dielectric constant of paper is k=3.7 . The capac
Pavlova-9 [17]

Answer:

k =  6.72

Explanation:

K of paper = 3.7

k of air = 1

Given that charge Q on the capacitor is constant because cell is disconnected from the circuit. So

V = Q / C = 2.5

Capacity becomes C / 3.7 in air .

capacity becomes C/3.7 when paper is replaced by air .

V₁ = Q / (C/3.7)

= 3.7 Q/C

3.7 x 2.5

= 9.25 V

In the second case ,

capacitance  due to new unknown dielectric k

= C/3.7 x k

= kC / 3.7 ( Capacitance in air is C/3.7 )

V ( new ) = Q / ( kC/3.7 )

= 3.7 Q/kC

.55 x 2.5 = 3.7 x( 2.5 / k )

k = 3.7 / .55

= 6.72

7 0
3 years ago
The electron drift speed in a metal wire is exceedingly slow. Yet, when you turnon the light switch the light begins to illumina
elixir [45]

Explanation:

The misunderstanding here is that the thing that turns on the light bulb is not the same electrons near the light switch. So, the electrons near the switch is not moving all the way across the circuit instantly. The electrons are distributed across the wire. When the light switch is turned on, the circuit is connected and there is a potential difference between the bulb and the source. This potential difference creates an electric field, and free electrons move under the influence of this electric field according to Coulomb's Law. When they start to move the electrons closest to the bulb causes the bulb to glow.

So, the important factor here is not the drift velocity of the electrons but the number of electrons and the strength of the electric field.

6 0
3 years ago
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Which way(s) can increase the c
Sav [38]

Answer:

A, B and F are the right answers

Explanation:

The formula is a_{c} = v^{2} / r

A) Increasing both the radius and the speed by a factor of 9

a_{c} = (9v)^{2} / (9r) = 9v^{2} / r

<u><em>which means the acceleration will increase by a factor of 9</em></u>

B) Keeping the speed fixed and decreasing the radius by a factor of 9

a_{c} = (v)^{2} / (r/9) = 9v^{2} / r

<u><em>which means the acceleration will increase by a factor of 9</em></u>

C) Keeping the radius fixed and increasing the speed by a factor of 9

a_{c} = (9v)^{2} / (r) = 81v^{2} / r

It will increase the acceleration 81 times

D) Keeping the speed fixed and increasing the radius by a factor of 9

a_{c} = (v)^{2} / (9r) = v^{2} / 9r

It will decrease the acceleration by 9 times

E) decreasing both the radius and the speed by a factor of 9

a_{c} = (v/9)^{2} / (r/9) = v^{2} / 9r

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F) Keeping the radius fixed and increasing the speed by a factor of 3

a_{c} = (3v)^{2} / (r) = 9v^{2} / r

<u><em>It will increase the acceleration by 9 times </em></u>

4 0
3 years ago
Plisssss you can help me pliss
Nesterboy [21]
For the first one it’s the guh sound
And the second one it’s the kuh sound
6 0
3 years ago
What best illustrates that light behaves like particles
Ira Lisetskai [31]
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3 0
3 years ago
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