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distance traveled by a uniformly accelerated bike is given as

here we know that



now we will have from above equation


so it will cover the total distance of 300 m
m₁ = mass of sample of copper = m₂ = mass of sample of aluminum = 5 g
T = initial temperature of copper = initial temperature of aluminum
T₁ = final temperature of copper
T₂ = final temperature of aluminum
c₁ = specific heat of copper = 0.09 cal/g°C
c₂ = specific heat of aluminum = 0.22 cal/g°C
Since both receive same amount of heat, hence
Q₁ = Q₂
m₁ c₁ (T₁ - T) = m₂ c₂ (T₂ - T)
(5) (0.09) (T₁ - T) = (5) (0.22) (T₂ - T)
T₁ - T = (2.44) (T₂ - T)
Change in temperature of copper = (2.44) change in temperature of aluminum
hence the correct choice is
c. The copper will get hotter than the aluminum.
Answer:
3469.788 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
First rocket

Second rocket

When this will collide the total distance they would have covered would be 6000 m.


Hence at 13.72 seconds they will collide assuming they are launched at the same time.

The second rocket would have gone 3469.788 m when they collide
Answer:
The correct answer is "
".
Explanation:
According to the question,
The work will be:
⇒ 




Thus the above is the correct answer.