Answer:
The speed and direction of the two players immediately after the tackle are 3.3 m/s and 53.4° South of West
Explanation:
given information:
mass of fullback,
= 92 kg
speed of full back,
= 5.8 to south
mass of lineman,
=110 kg
speed of lineman,
= 3.6
according to conservation energy,
assume that the collision is perfectly inelastic, thus
initial momentum = final momentum
=
'
m₁v₁ = (m₁+m₂)
'
' = m₁v₁/(m₁+m₂)
= (92) (5.8)/(92+110)
= 2.64 m/s
=
'
m₂v₂ = (m₁+m₂)
'
' = m₁v₁/(m₁+m₂)
= (110) (3.6)/(92+110)
= 1.96 m/s
thus,
' = √
'²+
'²
= 3.3 m/s
then, the direction of the two players is
θ = 90 - tan⁻¹(
'/
')
= 90 - tan⁻¹(1.96/2.64)
= 53.4° South of West
Answer:
Electrical energy. Jump to navigation Jump to search. Electrical energy is energy derived from electric potential energy or kinetic energy. When used loosely, electrical energy refers to energy that has been converted from electric potential energy
Explanation:
Answer:

Explanation:
The acceleration of the bycicle is given by:

where
v = 20 m/s is the final velocity of the bike
u = 40 m/s is the initial velocity
t = 5 s is the time interval
Substituting numbers, we find

and the acceleration is negative, which means that the bycicle is slowing down.
Answer:
Part a)
T = 0.52 s
Part b)

Part c)

Explanation:
As we know that the particle move from its maximum displacement to its mean position in t = 0.13 s
so total time period of the particle is given as

now we have
Part a)
T = time to complete one oscillation
so here it will move to and fro for one complete oscillation
so T = 0.52 s
Part b)
As we know that frequency and time period related to each other as



Part c)
As we know that
wavelength = 1.9 m
frequency = 1.92 Hz
so wave speed is given as


