Question

Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g·K. If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature? *HINT check what number the question is asking for>
A. –22.7°C
B. 36.7°C
C. 42.7°C
D. 62.7°C
E. none of these choices is correct

Answer 1

Answer: $62.7^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= 16.7 kJ = 16700 J  (1kJ=1000J)

m= mass of benzene = 225 g

c = specific heat capacity = 1.74 J/gK

Initial temperature of the water = $T_i$ = 20.0°C  = 293 k  $0^0C=273K$

Final temperature of the water = $T_f$  = ?

Change in temperature ,$\Delta T=T_f-T_i$

Putting in the values, we get:

$16700=225\times 1.74\times (T_f-293)$

$T_f=335.6K=62.7^0C$

The  final temperature will be $62.7^0C$