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3 years ago

Given the equation I = Q/t, solve for t.

Chemistry

1 answer:

larisa86 [58]3 years ago

5 0

Answer: $t=\frac{Q}{I}$

Explanation:

$I=\frac{Q}{t}$

Multiply by t on both sides.

$t*I=\frac{Q}{t}*t$

$tI=Q$

Now divide by I to isolate t.

$\frac{tI}{I}=\frac{Q}{I}$

$t=\frac{Q}{I}$

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A gas occupies 25.3 at pressure of 790.5 mmHg. Determine the volume if the pressure is reduced to 8.04 mmHg

taurus [48]

Answer:

2487.51.

Explanation:

As per Boyle's law temperature remaining constant the volume of an ideal gas is inversely proportional to its pressure.

pV= k

therefore, p1V1 = p2V2

here V1 = 25.3, p2 = 8.04mm Hg

pressure p1 = 790.5 mm Hg

this means that

25.3×790.5 = 8.04V2

⇒V2= 2487.51

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3 years ago

During laparoscopic surgery , carbon dioxide gas is used to expand the abdomen to help create a larger working space. If 4.80 L

Studentka2010 [4]

Answer:

5.37 L

Explanation:

To solve this problem we need to use the PV=nRT equation.

First we calculate the amount of CO₂, using the initial given conditions for P, V and T:

P = 785 mmHg ⇒ 785/760 = 1.03 atm

V = 4.80 L

T = 18 °C ⇒ 18 + 273.16 = 291.16 K

1.03 atm * 4.80 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 291.16 K

We solve for n:

n = 0.207 mol

Then we use that value of n for another PV=nRT equation, where T=37 °C (310.16K) and P = 745 mmHg (0.98 atm).

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And we solve for V:

V = 5.37 L

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When fluorine gas combines with water vapor, the following reactions occurs.

jonny [76]

Hello!

The Chemical reaction is the following:

2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)

If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

$2 L F_2* \frac{2 L H_2O}{2 L F_2}=2 L H_2O \\ \\ 2 L F_2* \frac{1 mol O_2}{2 L F_2}=1 mol O_2 \\ \\ 2 L F_2* \frac{4 mol HF}{2 mol F_2}= 4 mol HF$

So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.

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