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Elanso [62]
3 years ago
10

When filling degenerate orbitals, electrons fill them singly first, with parallel spins is known as When filling degenerate orbi

tals, electrons fill them singly first, with parallel spins is known as:
A. Hund's rule
B. Heisenberg uncertainty principle
C. Aufbau principle
D. Pauli exclusion principle
Chemistry
1 answer:
stiv31 [10]3 years ago
5 0

Answer : The correct option is, (A) Hund's rule

Explanation :

Hund's rule : It states that the electrons are singly filled first in each orbital having same spin, then only pairing occurs.

Heisenberg  uncertainty principle : It is defined as the position and the momentum both can not be determined simultaneously.

Aufbau principle : It states that the atom or ion that present in the ground state, the lowest energy level will be filled first before occupying the higher levels.

Pauli Exclusion Principle : It states that no two electrons present in an atom or a molecule can have the same set of the four quantum numbers.

Hence, the correct option is, (A) Hund's rule

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Provide 3 examples of substances that are mixtures and list the substances in them
Vedmedyk [2.9K]

Answer:

Water and salt = salt water

Oxygen and water = sea foam

Smoke and fog = smog

Explanation:

Hope this helped, nya~ :3

3 0
3 years ago
Read 2 more answers
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

8 0
3 years ago
Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pKa
GuDViN [60]

Answer:

a  H2CO3 b HCO3- and c H+ and HCO3-

Explanation:

As the pKa value of phenol is more than that of carbonic acid(H2CO3), the carbonic acid will have high Ka value than that of phenol.

  The acid that contain high Ka value act as stong acid.From that point of view H2CO3 is a strong acid than phenol as the Ka value of carbonic acid is greater than that of phenol.

  The conjugate base of H2CO3 is bicarbonate ion(HCO3-)

c The species that predorminates at equilibrium are H+ and HCO3-

8 0
3 years ago
How many moles of hydrogen are needed to completely react with 2 moles of nitrogen
Natali5045456 [20]
Assuming ammonia is the product of this reaction:

N2+3H2--->2NH3

2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2

You would need 6 mol of hydrogen gas to completely react with 2 mol of nitrogen. 
5 0
3 years ago
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