Explanation:
Given parameters:
Time of drop = 3.82s
Unknown:
Final velocity of the ball = ?
Height of fall = ?
Solution:
To solve this problem, we apply the appropriate motion equation.
To find the final velocity;
v = u + gt
v is the unknown final velocity
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time
v = 0 + 9.8 x 3.82 = 37.4m/s
Height of drop;
H = ut +
gt²
So;
H = (0 x 3.82) + (
x 9.8 x 3.82²) = 71.5m
Answer:
Equivalent resistance: 13.589 Ω
Explanation:
R series = R1 + R2 + R3 ...

Find the equivalent resistance of the right branch of the circuit:


Answer:
x = 0.176 m
Explanation:
For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.
Let's use trigonometry to decompose the tension
sin 60 =
/ T
T_{y} = T sin 60
cos 60 = Tₓ / T
Tₓ = T cos 60
we apply the equation
∑ τ = 0
-W L / 2 - w x + T_{y} L = 0
the length of the bar is L = 6m
-Mg 6/2 - m g x + T sin 60 6 = 0
x = (6 T sin 60 - 3 M g) / mg
let's calculate
let's use the maximum tension that resists the cable T = 900 N
x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)
x = (4676 - 5880) / 6860
x = - 0.176 m
Therefore the block can be up to 0.176m to keep the system in balance.
Explanation:
advantage: Easy to design and build the circuit
disadvantage: if one component in a series circuit fails, then all the components in the circuit fail because the circuit has been broken.
hope it helps!
Answer:

Explanation:
The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:

where:
is the vaacuum permeability
I is the current in the wire
r is the distance from the wire
The direction of the magnetic field lines is tangential to concentric circles around the wire.
In this problem, we have:
is the current in the wire
is the distance from the wire
Solving for B, we find the magnitude of the magnetic field:
