Answer:
774.8 secs
Explanation:
distance(d)= speed(v)* time(t)
calculate speed:
refractive index = speed of light (c)/ speed of light in medium (v)
1.56 = 3*10^8*v
v=192307692.3 m/s
d = v *t
t = d/v
on substituting values:
t = 774.8 secs
Answer:
1.125m/s^2
Explanation:
Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically
v^2= u^2+2as
Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.
a = ?
u = 0m/s
v = 15m/s
s = 100m
Substituting the values into the formula above
v^2= u^2+2as
15^2=0^2+2×a×100
225= 0+200a
225= 200a
Divide both sides by 200
225/200 = 200a/200
a= 1.125m/s^2
Hence the acceleration of the car is 1.125m/s^2.
Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s
Answer:
p(a) * p(b) = .01923
p(b) = .01923 / .07692 = .2500
