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dezoksy [38]
3 years ago
14

A mass of 100.0 g of solute is dissolved in water so that 850. mL of a 0.7500 M solution has been prepared. What is the molar ma

ss of the solute?
Chemistry
1 answer:
zmey [24]3 years ago
8 0

Answer:

156.86 g / mol

Explanation:

We start from the molarity law  

Cm = n / V

n = w / M

then

Cm = (w / M) / V

Cm = w / (M × V)

where:

Cm is the molarity  

n number of moles

w a mass of the solute  

M is the molar mass of the solute (which is needed)

V the volume of the solution in liters

Then the M can be calculated as following:  

M = w / (Cm × V)

M = 100 / (0.75 × 0.85) = 156.86 g / mol

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Explanation:

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You are cutting each concentration in half, so

\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}

Then,

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Mathematically, the ideal gas equation is given as:

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