Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
Answer:
240000 Joules
Explanation:
Applying,
The work that must be done by the frictional force of the brake to stop the car must be equal to the kinetic energy of the car.
W = mv²/2.................. Equation 1
Where W = work done by the frictional force of the brake, m = mass of the car, v = velocity of the car.
From the question,
Given: m = 1200 kg, v = 20 m/s
Substitute these values into equation 1
W = (1200×20²)/2
W = 240000 Joules
F~1/r²
doubling the distance r, Decreases the force by ¼
Given:
Dy= 20 m
Vi = 5.0 m/s horizontally
A=9.81 m/s^2
Find:
Horizontal displacement
Solution:
D=ViT+(1/2)AT^2
Dy=(1/2)AT^2
T^2=Dy/(1/2)A
T=sqrt(Dy/(1/2)A)
T=sqrt(20/4.905)
T=2.0s
Dx=ViT
Dx=(5.0)(2.0)
Dx=10. meters
