Answer:
Explanation:
stiffness k = 160
m = 10
angular frequency ω = 
= 
= 4
ω = 4
Let x = 4 - A sinωt
when t = 0
x = 4 in
when t = 2 s , x = - 4
- 4 = 4 - A sinωt
8 = A sin 4 x 2
8 = A sin8
A = 8 / sin 8
= 8 / .989
= 8.09 in .
x = 4 - A sinωt
dx / dt = - Aω cosωt
v = - Aω cosωt
for t = 0
v = - Aω
= - 8.09 x 4
= - 32.36 in / s
initial velocity v = - 32.36 in /s
displacement x for t = 4s
x = 4 - 8.09 sin 4 x 4
= 4 - 8.09 sin 16
= 4 - 8.09 x - .2879
= 4 + 2.33
= 6.33 in.
c ) Amplitude of vibration A = 8.09 in .as calculated above .
Answer:
0.0231 m/s
Explanation:
Given the question :
A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?
Distance walked south = 2.099 metre
Time taken = 29.01s
Distance walked north = 1.429 metre
Average Velocity = Displacement / time
The Displacement is hence,
(2.099 m - 1.429m) = 0.67m
Average Velocity = 0.67m / 29.01s
Average Velocity = 0.02309 m/s
Average Velocity = 0.0231 m/s
Answer:
Its duration is 1.85*10⁻³ s or 1.85 ms
Explanation:
The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).
The intensity of electric current is expressed as:

where:
I: Intensity expressed in Amps (A)
Q: Electric charge expressed in Coulombs (C)
t: Time expressed in seconds (s)
Being:
Replacing:

Solving:
19500 A*t= 36 C

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)
<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>