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MaRussiya [10]
3 years ago
8

Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
First we should convert 14.4 km into meters using the conversion factor 1km = 1000m; thus, 14.4 km = 14,400 m. Next, we should convert all minutes into seconds <span>using the conversion factor 1 min = 60 seconds; thus, 40 mins = 2400 seconds while 20 minutes = 1200 seconds. 
Speed = distance over time
Amy's speed = 14400 m / 2400 sec = 6m/s
Bill's time is 1200 sec + Amy's which is 2400 sec
Bill's speed = 14400m / 3600 sec  = 4 m/s

Therefore, Amy is faster than Bill with 2 m/s difference.</span>
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The correct answer Is C
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lora16 [44]
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A SDOF undamped system is set into free vibration with an initial displacement and an initial velocity. The mass of the system i
loris [4]

Answer:

Explanation:

stiffness k = 160

m = 10

angular frequency ω = \sqrt{\frac{k}{m} }

= \sqrt{\frac{160}{10} }

= 4

ω  = 4

Let x = 4 - A sinωt

when t = 0

x = 4 in

when t = 2 s , x = - 4

- 4 = 4 - A sinωt

8  = A sin 4 x 2

8 = A sin8

A = 8 / sin 8

= 8 / .989

= 8.09 in .

x = 4 - A sinωt

dx / dt = - Aω cosωt

v =  - Aω cosωt

for t = 0

v = - Aω

= - 8.09 x 4

= - 32.36 in / s

initial velocity v = - 32.36 in /s

displacement x for t = 4s

x = 4 - 8.09 sin 4 x 4

= 4 - 8.09 sin 16

= 4 - 8.09 x - .2879

= 4 + 2.33

= 6.33  in.

c ) Amplitude of vibration A = 8.09 in .as calculated above .

4 0
3 years ago
A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. Wha
gtnhenbr [62]

Answer:

0.0231 m/s

Explanation:

Given the question :

A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?

Distance walked south = 2.099 metre

Time taken = 29.01s

Distance walked north = 1.429 metre

Average Velocity = Displacement / time

The Displacement is hence,

(2.099 m - 1.429m) = 0.67m

Average Velocity = 0.67m / 29.01s

Average Velocity = 0.02309 m/s

Average Velocity = 0.0231 m/s

8 0
4 years ago
A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?
Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

I=\frac{Q}{t}

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

  • I= 19500 A
  • Q=36 C
  • t=?

Replacing:

19500 A=\frac{36 C}{t}

Solving:

19500 A*t= 36 C

t=\frac{36 C}{19500 A}

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

8 0
3 years ago
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