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morpeh [17]
3 years ago
9

You are walking back toward the back of a bus that is moving forward with a constant velocity. Describe your motion relative to

the bus and relative to a point on the ground.
Physics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer: Relative to the bus, you are stationary. Relative to a point on the ground, you are walking forward with velocity  equal to the velocity of the bus.

As a person walks toward the back of a bus, they are walking towards a stationary object according to their own perspective. However, from an outside perspective, the bus is moving forward with a constant velocity and so relative to that point in motion, you are actually walking backwards with respect to it. This difference in motion means you would not be able have the same experience as the person on the bus when getting off because when you get off you would stop while they continue going forward. The last sentence could be considered a footnote because it only applies if this was an actual situation rather than just an analogy question in a physics test.

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A flat surface is in a uniform magnetic field. Given only the area of the surface and the magnetic flux through the surface, it
Tasya [4]

Answer:

Given the area A of a flat surface and the magnetic flux through the surface \Phi it is possible to calculate the magnitude \frac{\Phi}{A}=B\ cos \theta.

Explanation:

The magnetic flux gives an idea of how many magnetic field lines are passing through a surface. The SI unit of the magnetic flux \Phi is the weber (Wb), of the magnetic field B is the tesla (T) and of the area A is (m^{2}). So 1 Wb=1 T.m².

For a flat surface S of area A in a uniform magnetic field B, with \theta being the angle between the vector normal to the surface S and the direction of the magnetic field B, we define the magnetic flux through the surface as:

                                                     \Phi=B\ A\ cos\theta

We are told the values of \Phi and B, then we can calculate the magnitude

                                                      \frac{\Phi}{A}=B\ cos\theta

3 0
3 years ago
Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has twice as much
Tcecarenko [31]

Answer:

D. All of the above.

Explanation:

Iron has a constant density, which means 2-kg block will have twice as much volume as 1-kg block; therefore, choice A is correct.

Inertia is defined by the equation F = ma: it measures how hard it is to change the motion of an object. The inertia of the the 1-kg solid iron is

F = 1a,

And the inertia of the 2-kg solid iron is

F = 2a,

which is twice as much that of the 1-kg block; therefore, choice B is correct.

The mass of the 2-kg block is twice as much as that of the 1-kg block; therefore, choice C is also correct.

Thus, all of the choices are correct (D).

3 0
3 years ago
A pulley system lifts a 1345 n weight a distance of 0.975m. Paul pulls the rope a distance of 3.90m, exerting a force of 375N. A
Rashid [163]

A. IMA: 4

The Ideal Mechanical Advantage (IMA) is given by:

IMA = \frac{d_i}{d_o}

where

d_i is the input distance

d_o is the output distance

For the pulley system in this problem, d_i = 3.90 m and d_o = 0.975 m, so the IMA is

IMA=\frac{3.90 m}{0.975 m}=4


B. MA: 3.59

The actual mechanical advantage (AMA), or simply the Mechanical Advantage (MA), is given by

MA=\frac{F_o}{F_i}

where F_o is the output force and F_i is the input force. For the pulley system in this problem, F_i = 375 N and F_o = 1345 N, so the MA is

MA=\frac{1345 N}{375 N}=3.59


C. Efficiency: 89.8 %

The efficiency of a machine is equal to the ratio between the MA and the AMA:

\eta = \frac{MA}{AMA} \cdot 100

Therefore, in this case,

\eta=\frac{3.59}{4}\cdot 100=0.898=89.8 \%

3 0
3 years ago
Hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed
Yanka [14]

Answer:

Sorry I'm wrong The person above is correct.

I tried.

4 0
3 years ago
Read 2 more answers
If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be
Novosadov [1.4K]
It would be Joules.
Workdone is measured in Joules.
Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
          = kgms⁻²

Distance = m

So, Force * distance
       kgms⁻² * m

Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
m¹ * m¹ = m¹⁺¹ = m²
s⁻² is also = s / 2





4 0
3 years ago
Read 2 more answers
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