All categories

3 years ago

Macro shots of flowers will typically have a shallow depth of field. True or False?

Physics

2 answers:

SSSSS [86.1K]3 years ago

5 0

It is TRUE that macro shots of flowers will typically have a shallow depth of field.

Macro photography (or photomacrography or macrography, and sometimes macrophotography), is extreme close-up photography, usually of very small subjects, in which the size of the subject in the photograph is greater than life size (though macrophotography technically refers to the art of making very largephotographs).

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

tigry1 [53]3 years ago

3 0

Answer:

true

Explanation:

You might be interested in

In which medium does sound travel the fastest?

AURORKA [14]

Answer:

Solids

Explanation:

The speed of sound is different in different mediums. Among solids, liquids, and gases, sound travels faster through solids. The particles in solids are more closes as compared to liquids and gases.

3 0

2 years ago

1. A base-ball of mass 0.3kg approaches the bat at a speed of 30 miles/hour and when the ball hits the bat for 0.5 s, it started

andre [41]

Answer:

I = 27kg.mi/h

Explanation:

In order to calculate the impulse of the ball, you use the following formula:

$I=m\Delta v$ $=m(v-v_o)$ (1)

m: mass of the ball = 0.3kg

v: speed of the ball after the bat hit it = 60mi/h

vo: speed of the ball before the bat hit it = 30mi/h

You replace the values of all parameters in the equation (1):

$I=(0.3kg)(60mi/h-(-30mi/h))=27kg\frac{mi}{h}$

where the minus sign of the initial velocity means that the motion of the ball is opposite to the final direction of such a motion.

The imulpse of the ball is 27 kg.miles/hour

5 0

3 years ago

Eric has a mass of 80 kgkg. He is standing on a scale in an elevator that is accelerating downward at 1.7 m/s2m/s2. What is the

kolezko [41]

Answer:

The answer will be 936 N.

Explanation:

Given that

m = 80 kg

Acceleration of the elevator , a= 1.7 m/s² ( upward)

The gravity force on the mass = m g

The reading on the scale = F N

Now by applying the Newton's second law

F - m g = ma

F= m g + m a

F= m ( g +a )

F= 80 ( 10 + 1.7 ) N ( take g= 10 m/s²)

F=80 x 11.7 N

F= 936 N

Therefore the reading on the scale will be 936 N.

The answer will be 936 N.

5 0

3 years ago

Need answer fast plz

vazorg [7]

Answer:

a = 1.20m\ $s^{2}$

Explanation:

225 x 9.8

= 441N

710 - 441

= 269N

$\frac{269}{225}$ = 1.19

a = 1.20

8 0

2 years ago

Students perform a set of experiments by placing a block of mass m against a spring, compressing the spring a distance x along a

Verizon [17]

Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

The statement that indicates how the relationship between v and x changes is; As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x.

Reasons:

The energy given to the block by the spring = $\mathbf{0.5 \cdot k \cdot x^2}$

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = $0.5 \cdot k \cdot x^2$ = kinetic energy of

block = $0.5 \cdot m \cdot v^2$

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = $\mathbf{0.5 \cdot k \cdot x^2}$

The force of the weight of the block on the string, $F = m \cdot g \cdot sin(\theta)$

The energy given to the block = $0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta)$ = The kinetic energy of block as it leaves the spring = $\mathbf{0.5 \cdot m \cdot v^2}$

Which gives;

$0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta) = 0.5 \cdot m \cdot v^2$

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and c are constants

The graph of the equation a·x² + c·v² = b is an ellipse

Therefore;

As x increases, v increases, however, the value of v obtained will be lesser than the same value of x as when the block is on a flat plane.

Please find attached a drawing related to the question obtained from a similar question online

The possible question options are;

As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x

The relationship is no longer linear and v will be more for the same value of x

The relationship is still linear, with lesser value of v

The relationship is still linear, with higher value of v

The relationship is still linear, but vary inversely, such that as x increases, v decreases

Learn more here:

brainly.com/question/9134528

6 0

2 years ago