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svetlana [45]
3 years ago
5

Describe how NH3 and CF4 satisfies the octet for all atoms.

Chemistry
1 answer:
MariettaO [177]3 years ago
4 0
Let's start with ammonia (NH3)
A nitrogen atom has five valence electrons, and it wants a total of eight. It bonds with three hydrogen atoms, and "shares" one of its electrons with each hydrogen atom. The nitrogen atom now has six shared electrons and two unshared electrons, meaning the nitrogen atom now has eight. Hydrogen, on the other hand is special, as it only really wants two electrons in its outer shell, so it has a total of 2 shared electrons, and the octet or "Noble gas" rule is fulfilled, as hydrogen would then be like the nearest noble gas, helium.

For CF4, the explanation is much more simple. Each fluorine has seven outer electrons, so it wants to gain one more. Carbon has four electrons, and it wants to gain four. So, carbon shares one of each of its electrons with one of each fluorine's, making the carbon have eight electrons, and each fluorine has eight as well.
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Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Question 1: <em>Turn 25 coins tails up. You now have 50% parent material and 50% daughter material. What is the half life of this substance? (20 Points)</em>


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Question 2: <em>Imagine that another half life has gone by. Remember that ONLY the parent material can change to the daughter material. Turn over your pennies to represent the passing of another half life. How much total parent material and how much total daughter material do you now have? You may express your answer in number of pennies or in %. (Note: Since you cannot turn over half a penny, round the actual number of pennies you would turn over up.) (20 points)</em>


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Question 3: <em>How many half lives will pass before you have only 3 pennies that are parent material and 47 pennies that are daughter material? (20 Points)</em>


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Based upon the given information from all the questions, and based upon our answers we can assume this:

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<em>For future reference please do not post as complex questions like this, if you do (post a question that is similar to this) please state the following information:</em>

<em>"All questions posted in this post relate to one-another and cannot be answered without the other questions..."</em>

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