Answer:
the wheels and force of your foot pushing off of the ground.
Answer:
on the right side, because it is a product
Explanation:
photosynthesis is the chemical reaction with the help of which plants produce chemical energy with the help of light energy.
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The general standard for writing chemical reaction is that
- The chemical which are input to the process of chemical reaction are written on left hand side . They are known as reactant.
- The output of chemical reaction are written on right side. They are termed as product.
- Transition of reactant to product is shown by arrow.
Chemical reaction for photosynthesis is given by below equation
6CO2 + 12H2O + light ----------------> C6H12O6 + 6O2 + 6H2O
We can see that 6 molecules of light combines with 12 molecules of water to give one molecule of glucose and 6 molecules of both water and oxygen.
As, oxygen is the output of photosynthesis process, it is written on the right-hand side of equation and is product of this reaction.
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Thus, of the options given below for
In an equation for photosynthesis does oxygen belong
on the right side, because it is a product
Answer: element
Explanation:
It only has one type of atom making it a element
From the calculation, the pH of the solution is 4.85.
<h3>What is the pH?</h3>
The pH is defined as the hydrogen ion concentration of the solution. We have the ICE table as;
HA + H2O ⇔ H3O^+ + A^-
I 0.335 0 0
C -x +x +x
E 0.335 - x x x
Ka = 1 * 10^-14/Kb
Ka = 1 * 10^-14/1.8 × 10^–5
Ka = 5.56 * 10^-10
Ka = [H3O^+] [A^-]/[HA]
But [H3O^+] = [A^-] = x
5.56 * 10^-10 = x^2/ 0.335 - x
5.56 * 10^-10(0.335 - x ) = x^2
1.86 * 10^-10 - 5.56 * 10^-10x = x^2
x^2 + 5.56 * 10^-10x - 1.86 * 10^-10 = 0
x=0.000014 M
Now;
pH = -log 0.000014 M
pH = 4.85
Learn more about pH:brainly.com/question/15289741
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A) Nitrogen has an ATOMIC mass number of 14, but nitrogen gas consists of N₂ molecules, so the mass to use in this problem is 28 g/mol. Rates of effusion ∝ 1/√(mass), so
<span>√(mass unknown) /√28 = (rate N₂ effusion)/(rate unknown effusion) = 1.59 </span>
<span>∴ mass unknown = (1.59)²(28) = 70.78 g/mol </span>
<span>B) One possible gas that comes close for this mass is NF₃.</span>
