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3 years ago

A 34.8 kg runner has a kinetic energy of 1.09 x 10³ J. What is the speed of the runner?

Physics

1 answer:

Alchen [17]3 years ago

3 0

Answer:

7.91 m/s

Explanation:

Speed: This can be defined as the ratio of this to time. Speed can also be the magnitude of a velocity or speed is velocity without direction.

The S.I unit of speed is m/s.

From the question,

K.E = 1/2(mv²)................ Equation 1

Where K.E = Kinetic Energy, m = mass of the runner, v = velocity of the runner.

make v the subject of the equation

v = √(2K.E/m).................Equation 2

Given: K.E = 1.09×10³ J, m = 34.8 kg.

Substitute into equation 2

v = √(2× 1.09×10³/34.8)

v = √(62.64)

v = 7.91 m/s.

Hence the speed of the runner = 7.91 m/s

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Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the

Doss [256]

Answer:

$v_{su} = 19.44 m/s$

Explanation:

$m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg$

$T=9.29x10^8\\r_{o}=1.43x10^{12}$

If the sun considered as x=0 on the axis to put the center of the mass as a:

$m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}$

solve to r1

$r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}$

$r_1=1.428x10^9m$

Now convert to coordinates centered on the center of mass. call the new coordinates x' and y' (we won't need y'). Now since in the sun centered coordinates the angular momentum was

$L = \frac{m_{sa}*2*pi*r_1^2}{T}$

where T = orbital period

then L'(x',y') = L(x) by conservation of angular momentum. So that means

$L_{sun}=\frac{m_{sa}*2*\pi *( 2r_{o}*r_1 -r_1^2)}{T}$

Since

$L_{su}= m_{su}*v_{su}*r_1$

then

$v_{su}=\frac{m_{sa}*2*pi*(2r_{o}*r_{1}-r_{1}^2)}{T*m_{sa}*r_1}$

$v_{su} = 19.44 m/s$

7 0

4 years ago

Please help me I’ll mark brainless .

Ivan

The mass is 10.811 hope this helps

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3 years ago

True or False:

bulgar [2K]

Answer:

False

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False

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The kind of heat transfer that travels through space in electromagnetic waves is?

Masteriza [31]

Answer:

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Explanation:

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Name the material used to transfer of charges from one body to other

Evgesh-ka [11]

Answer:

conductor

Explanation:

A "conductor" is a material that allows the charges to pass freely from one body to the other. This causes a movement among the electrons and this means that the charge will be passed entirely to the object receiving it. This is also called "conductive material."

Examples of conductors are: copper, aluminum, gold, silver, seawater, etc.

The opposite of conductors are called "insulators." These do not allow the free movement of charges from one object to the other.

Examples of insulators: plastic, rubber, paper, glass, wool, dry air, etc.

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3 years ago