T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r
where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,
Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r
Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.
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How do you ask a question but don’t know the answer we will never know
Huh? Wheres the question at?
I think it’s B because we aren’t looking for Vf
Answer:
A = 5.6μs
B = 178.57kHz
C = 2.8μs
Explanation:
A. It takes ¼ of the period of the circuit before the total energy is converted from electrical energy in the capacitor to magnetic energy in the inductor.
t = T/4
T = 4*t
T = 4 * 1.4 = 5.6μs
B. f = 1/T
Frequency is the inverse of period
f = 1 / 5.6*10⁻⁶
f = 178571.4286Hz
f = 178.57kHz
C. time taken for maximum energy to occur is T/2
t = 5.6 / 2 = 2.8μs
