The change in energy is about 3.68 eV
<h3>Further explanation</h3>
The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :
<em>E = Energi of A Photon ( Joule )</em>
<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>
<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
<em>E = Energi of A Photon ( Joule )</em>
<em>m = Mass of an Electron ( kg )</em>
<em>v = Electron Release Speed ( m/s )</em>
<em>Ф = Work Function of Metal ( Joule )</em>
<em>q = Charge of an Electron ( Coulomb )</em>
<em>V = Stopping Potential ( Volt )</em>
Let us now tackle the problem !
<u>Given:</u>
f = 8.88 × 10¹⁴ Hz
h = 6.63 × 10⁻³⁴ Js
<u>Unknown:</u>
ΔE = ?
<u>Solution:</u>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: College
Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light