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maria [59]
2 years ago
14

A semi has a net force of 13,000 N and is accelerating at a rate of 6.5 m/s^2. What is the mass of the semi? *

Physics
1 answer:
Evgen [1.6K]2 years ago
4 0

Example 1: An 850-kg car is accelerating at a rate of 2.4m/s2 to the right along a ... 2) A nonzero net force ΣF acting on mass M causes an acceleration a in it such that ΣF = Ma. The acceleration has the same direction as the applied net force. ... (b) Knowing that the crate is being pushed to the left by a 53-N force

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football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a
valkas [14]

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

<u>Given the following data;</u>

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

a. To find the momentum of A;

Momentum \; A = 110 * 2

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

Momentum \; B = 120 * 0

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

Total \; momentum = Momentum \; A + Momentum \; B

Substituting into the equation, we have;

Total \; momentum = 220 + 0

<em>Total momentum = 220 Kgm/s. </em>

7 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7
Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

7 0
3 years ago
Please need help with this
NeTakaya

<u>Note that</u>:

The gravitational potential energy = mgh

where m: is the mass, g: the acceleration due to the gravity and h is the height from the earth surface

Then, we can increase the gravitational potential energy by increasing the mass or the height from the earth surface

<u>In our question</u>, we can increase the gravitational potential energy by

<u>A) Strap a boulder to the car so that it wights more.</u>

7 0
3 years ago
It takes 5.0 seconds for a wave with a wavelength of 2.5 m to travel past your location. What’s the period of the wave. What is
Anna35 [415]
(a) Period of the wave
The period of a wave is the time needed for a complete cycle of the wave to pass through a certain point.
So, if an entire cycle of the wave passes through the given location in 5.0 seconds, this means that the period is equal to 5.0 s: T=5.0 s.

(b) Frequency of the wave
The frequency of a wave is defined as
f= \frac{1}{T}
since in our problem the period is T=5.0 s, the frequency is
f= \frac{1}{5.0 s}=0.2 Hz

(c) Speed of the wave
The speed of a wave is given by the following relationship between frequency f and wavelength \lambda:
v=f \lambda = (0.2 Hz)(2.5 m)=0.5 m/s

8 0
3 years ago
A stone is thrown straight upward and reaches a maximum height of 31.8 m above its
atroni [7]

Answer:

aral ka muna ng mabuti para maintindihan mo

7 0
3 years ago
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