I believe it is ice cubes.
I think it’s a or d one of those
Answer:
11.43g of Aluminum Hydroxide
Explanation:
Since we know that the sulfuric acid is the limiting reactant in this chemical reaction, we know that we are going to be left with excess aluminum hydroxide. So to find the amount of leftover aluminum hydroxide we are going to need to convert the given amount of sulfuric acid to the amount of aluminum hydroxide needed to react with the sulfuric acid.
![\frac{35g H_{2}SO_{4}}{1}*\frac{1 mole H_{2}SO_{4}}{98.079 g H_{2}SO_{4}} *\frac{2 moles Al(OH)_{3} }{3 moles H_{2}SO_{4}} * \frac{78.003 g Al(OH)_{3} }{1 mole Al(OH)_{3} } = 18.557 g Al(OH)_{3}](https://tex.z-dn.net/?f=%5Cfrac%7B35g%20H_%7B2%7DSO_%7B4%7D%7D%7B1%7D%2A%5Cfrac%7B1%20mole%20H_%7B2%7DSO_%7B4%7D%7D%7B98.079%20g%20H_%7B2%7DSO_%7B4%7D%7D%20%2A%5Cfrac%7B2%20moles%20Al%28OH%29_%7B3%7D%20%7D%7B3%20moles%20H_%7B2%7DSO_%7B4%7D%7D%20%2A%20%5Cfrac%7B78.003%20g%20Al%28OH%29_%7B3%7D%20%7D%7B1%20mole%20Al%28OH%29_%7B3%7D%20%7D%20%3D%2018.557%20g%20Al%28OH%29_%7B3%7D)
Once you do that, you need to subtract that number from the amount of aluminum hydroxide given to get the amount of left over aluminum hydroxide.
![30 g Al(OH)_{3} - 18.557 g Al(OH)_{3} = 11.43 g Al(OH)_{3}](https://tex.z-dn.net/?f=30%20g%20Al%28OH%29_%7B3%7D%20-%2018.557%20g%20Al%28OH%29_%7B3%7D%20%3D%2011.43%20g%20Al%28OH%29_%7B3%7D)
Hope this helps!
<span>an oxide of iron, magnesium, aluminum, and chromium</span>
1. Blood carries oxygen from your lungs to all your body cells. Carbon dioxide diffuses from your body cells into your blood. Your blood carries carbon dioxide to your lungs to be exhaled.
2. blood carries waste products from your cells to your kidneys to be removed
3. blood transport nutrients and other substances to your body cells
4. Cells and molecules in blood fight infections and help heal wounds