The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
<h3>What is an aqueous reaction in
equilibrium?</h3>
When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.
δG = − R T ln
R = universal gas constant 8.313
δG= 20. 46 kj/mol
T = 298 k or 24.4 in celcius.
substituting the value in the equation.
20. 46 kj/mol = 8.313 × 24.4 in celcius × K
K = 8.313 × 24.4 in celcius / 20. 46 kj/mo
k = 9.91 mol .
Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
Learn more about the aqueous reaction in equilibrium, here:
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Answer:
"Water and ethyl alcohol will both have dipole-dipole interactions.
Technically they will both have Hydrogen bonding, which is a type of dipole-dipole. This is due to the high electronegativity values of oxygen atoms compared to the carbon and hydrogen atoms the oxygens bond to. This causes regions of both of these molecules that have partial negative charges and other regions wind up with partial positive charges.
Hexane will not have any dipole-dipole interactions because it is a non-polar molecule. The intermolecular forces between hexane molecules will be dispersion forces."
Explanation:
Here is the place I found the answer: https://socratic.org/questions/which-of-these-structures-has-dipole-dipole-interactions-water-h2o-ethyl-alcohol
All of this answer belongs to that person. I do not own any of this information.
500 J (I've had the same question before so I know what answers there are... lol)
Answer:
Sample A is a pure substance
Sample B is a mixture
Explanation:
We are told that the when the yellow solid, sample A is ground it turned to orange colour and was then dissolved. Some part of the solid settled out at the bottom of the beaker while some part floated on top of the water. 50g of the solid was dissolved and 50.1g of the solid was recovered.
This implies that the substance is pure since the mass dissolved was almost the same mass recovered. The 0.1g addition in mass may result from incomplete drying of the solid.
For sample B, the distillation of the sample of density 0.77 g/ml left a fraction in the beaker with density 1.04 g/ml indicating that the substance is a mixture. Different components of a mixture possess different densities.
