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JulsSmile [24]
3 years ago
15

A compound is known to have an empirical formula of CH and a molecular mass of 78.11 g/ mom what is he molecular formula

Chemistry
1 answer:
timofeeve [1]3 years ago
5 0
Hope this helps you.

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The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t
slega [8]

Answer:

The catalyzed reaction will take time of 5.11\times 10^{-8} years.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate of reaction with catalyst

K_1 = rate of reaction without catalyst

Ea_2 = activation energy with catalyst  = 59.0 kJ/mol = 59000 J/mol

Ea_1 = activation energy without catalyst  = 184 kJ/mol = 184000 J/mol

R = gas constant

T = temperature = 600K

Now put all the given values in this formula, we get:

\frac{K_2}{K_1}=e^{\frac{184,000 kJ-59000 kJ}{R\times 300}}=7.632\times 10^{10}

The reaction enhances by 7.632\times 10^{10}  when catalyst is present.

Time taken by reaction without catalyzed = 3900 years

Time taken by reaction with catalyzed = x

x=\frac{3900 year}{7.632\times 10^{10}}=5.11\times 10^{-8} years

The catalyzed reaction will take time of 5.11\times 10^{-8} years.

8 0
3 years ago
what is an ordered arrangement of particles extends over a long distance in a solid, the material is called?
Artyom0805 [142]
Plasmodium is the best answer
5 0
4 years ago
Read 2 more answers
A horizontal row of the periodic table is usually referred to as a ____________
zaharov [31]

the answer is period

8 0
3 years ago
Read 2 more answers
Calculate the specific heat of a substance if a 35g sample absorbs 48 j as the temperature is raised from 293 k to 313 k
bulgar [2K]

Answer:

c = 0.07 j/g.k

Explanation:

Given data:

Mass of sample = 35 g

Heat absorbed = 48 j

Initial temperature = 293 K

Final temperature = 313 K

Specific heat of substance = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT = 313 k - 293 K

ΔT = 20 k

Now we will put the values in formula.

48 j = 35 g × c× 20 k

48 j = 700 g.k ×c

c = 48 j/700 g.k

c = 0.07 j/g.k

8 0
3 years ago
What material is least likely to be recognized as a mixture by looking under a microscope
I am Lyosha [343]
A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water.
6 0
3 years ago
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