The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.
<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>
The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.
The equation of the reaction is given below:

The mole ratio of both reactants and product is 1 : 1
molar mass of copper sulfate = 160 g
molar mass of Cu = 64
molar mass of iron = 56 g
- mole ratio of iron to copper = 1 : 1
moles of Cu in 1.5 g = 1.5/64 = 0.00234
mass of iron required = 0.00234 × 56 = 1.31 g of iron
Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.
Learn more about mole ratio at: brainly.com/question/19099163
You would take mass/volume to find the density. So, 12.8/2^3 is 1.6. The density of the cube is 1.6.
The ratio of atoms of potassium to ratio of atoms of oxygen is 2:1
Answer: 10 cm3
Explanation:
Mass of sample of steel (m) = 80 grams
density of sample of steel (p) = 8 g/cm3 samples volume (v) = ?
Since density is obtained by dividing mass by volume, the density of the steel sample is expressed as:
density = mass / volume
p = m / v
make v the subject formula
v = m / p
v = 80 grams / 8 g/cm3
v = 10 cm3
Thus, the samples volume is 10 cm3
Answer:
4.4 × 10^-7
3 × 10^5
Explanation:
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