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marshall27 [118]
4 years ago
15

Word Bank

Chemistry
1 answer:
kiruha [24]4 years ago
7 0
Kingdom, phylum or division, class, order, family, genus, species 
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Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of lig
Usimov [2.4K]

Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

n=2

Explanation:

From the question we are told that:

Wavelength \lambda=486nm=>486*10^{-9}

Generally the equation for Atom Transition is mathematically given by

\frac{1}{\lambda}=R_{\infty }(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where

Rydberg constant R_{\infty}=1.097*10^7

Therefore

\frac{1}{486*10^{-9}}=1.097*10^7*(\frac{1}{n_1^2}-\frac{1}{4^2})

(\frac{1}{n_1^2}-\frac{1}{4^2})=\frac{1}{486*10^{-9}*1.097*10^7}

n_1^2=3.98

n=1.99

n=2

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Why the is ratio of magnesium ions to chloride ions in MgCl2 is 1:2?
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You should read up on Proust's law, better known as the Law of Definite Proportions. This is a chemical law that defines your question more generally, on why the ratio of elements and ions are always fixed.

Basically, this compound Magnesium(II) Chloride is MgCl2 because it has the same number of protons, neutrons, and electrons all the way. This defines the properties of the compound or atom. 
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I am also pretty sure the answer is B, but give the answer above me Brainliest. Have a great day
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