Answer:
The final velocity of cart 1 is 3m/s
Explanation:
From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.
Momentum, P is given as mass x velocity.
ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
Assumptions:
- If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
- After the elastic collision, the two carts will move separately with different velocity
u₁ + u₂ = v₁ + v₂;
where;
u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively
v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively
1 m/s + 5 m/s = v₁ + 3m/s
6 m/s = v₁ + 3m/s
v₁ = 6 m/s - 3m/s = 3m/s
Therefore, the final velocity of cart 1 is 3m/s
When a cloud of gas and dust in space was disturbed, maybe by the explosion of a nearby star.This explosion made waves in space which squeezed the cloud of gas & dust.
The circuit is a parallel circuit.
Because even one light bulb is broken, the others are still lit. Therefore it is not a series circuit
You can use the impulse momentum theorem and just subtract the two momenta.
P1 - P2 = (16-1.2)(11.5e4)=1702000Ns
If you first worked out the force and integrated it over time the result is the same
