Answer:
a)
b)
Explanation:
<u>Given:</u>
a) when the initial velocity of the projectile is 0.520 times the escape velocity from the earth.
Let r be the radial distance from the earth's surface Let M be the mass of the Earth and R be the radius of the Earth
Now using conservation of Energy at earths surface and at distance r we have
b) when the Initial kinetic Energy of the projectile is 0.52 times the Kinetic Energy required to escape the Earth
Conservation of Energy we have
Distance = Speed × time
Distance = 31m/s × 13 seconds = 403m
To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.
The energy fluency is given by the equation
Where
The energy fluency
c = Activity of the source
r = distance
E = electric field
In the other hand we have the equation for current in materials, which is given by
Then replacing our values we have that
We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.
Now the energy fluency would be,
The uncollided flux density at the outer surface of the tank nearest the source is
Answer:
the can's kinetic energy is 0.42 J
Explanation:
given information:
Mass, m = 460 g = 0.46 kg
diameter, d = 6 cm, so r = d/2 = 6/2 = 3 cm = 0.03 m
velocity, v = 1.1 m/s
the kinetic energy of the can is the total of kinetic energy of the translation and rotational.
KE = I ω^2 +
where
I = and ω =
thus,
KE = ()^2 +
= +
= +
=
=
= 0.42 J