B. intermolecular attractions.
Answer:
Explanation:
Here, we want to get the new volume of the gas
What we need to know is the law that connects volume and pressure at constant temperature
The law that supports this is the Boyle's law
It states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature
Mathematically, we can have this as represented as:

We can proceed mathematically to solve as follows;
The question is incomplete, the complete question is shown in the image attached to this answer
Answer:
See explanation
Explanation:
15) The both diamonds- the diamond used as a grinding tool and the two -carat diamond both have the same density because density is an intensive or intrinsic property of a substance. It does not depend on the mass of the substance present.
16) Area of magnesium = Length * width = 0.104 * 10^2 cm * 2.52 * 10^-1 cm = 2.62 cm^2
Density = mass/area * thickness
Density * area * thickness = mass
thickness = mass/Density * area
thickness = 0.104 g/ 1.74g/cm3 * 2.62 cm^2
thickness = 0.0228 cm
Answer:
10573.9K
Explanation:
Using pressure law equation;
P1/T1 = P2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
P1 = 46mmHg
P2 = 760mmHg
T1 = 640K
T2 = ?
Using P1/T1 = P2/T2
46/640 = 760/T2
Cross multiply
640 × 760 = 46 × T2
486400 = 46T2
T2 = 486400 ÷ 46
T2 = 10573.9K
Answer : The enthalpy of combustion of
will be -1775 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The combustion of
will be,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

Now we are reversing the reaction 1, multiplying reaction 2 and 3 by 3 and then adding all the equations, we get :
(1)

(2)

(3)

The expression for enthalpy of combustion of
will be,



Therefore, the enthalpy of combustion of
will be -1775 kJ