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3 years ago

The continuous submarine mountain range which winds through all the oceans is called the mid-ocean

1 answer:

5 0

The continuous submarine mountain range which winds through all the oceans is called the mid-ocean ridge.
It is a form of a mountain which is found underwater, and it appeared there due to the movements of tectonic plates. It is responsible for the creation of new seafloor, meaning that the ground underwater changes constantly with the formation of these ridges.

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Your friends sit in a sled in the snow. If you apply a force pf 75 N to them, they have an acceleration of 0.9 m/s ^ 2. What is

Elza [17]

Answer:

Mass of the sled in the snow 83.33 kg.

Explanation:

Given that,

Force applied to move the sled in the snow (F) = 75N

$\text { Acceleration }(a)=0.9 \mathrm{m} / \mathrm{s}^{2}$

We know that

Newton's second law of motion is

$\text { Force }=\text { mass } \times \text { acceleration }$

F = ma (Or "force" is equal to "mass" times "acceleration".)

So if we move this around we can isolate mass and get mass

$\text { Mass }=\frac{\text { force }}{\text { accelearation }}$

$\mathrm{M}=\frac{75}{0.9}$

M = 83.33 kg

Mass of the sled in the snow 83.33 kg.

3 0

3 years ago

A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on

aliya0001 [1]

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

F = ma

solve for a

a = $\frac{F}{m}$

Substitution

$a = \frac{100}{400}$

Simplification and result

a = 0.25 m/s²

5 0

2 years ago

I AM........ INEVITABLE

Archy [21]

Answer:

that's nice very nice super duper nicer

5 0

3 years ago

The wavelength of the visible line in the hydrogen spectrum that corresponds to m = 5 in the Balmer equation is: A. 656 nm. B. 4

BaLLatris [955]

Answer:

The wavelength of the visible line in the hydrogen spectrum is 434 nm.

Explanation:

It is given that, the wavelength of the visible line in the hydrogen spectrum that corresponds to n₂ = 5 in the Balmer equation.

For Balmer series, the wave number is given by :

$\dfrac{1}{\lambda}=R(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})$

R is the Rydberg's constant

For Balmer series, n₁ = 2. So,

$\dfrac{1}{\lambda}=1.097\times 10^7\times (\dfrac{1}{2^2}-\dfrac{1}{5^2})$

$\lambda=4.34\times 10^{-7}\ m$

$\lambda=434\ nm$

So, the wavelength of the visible line in the hydrogen spectrum is 434 nm. Hence, this is the required solution.

6 0

2 years ago

In a circuit, a variable resistor is to be connected across a potential difference of 60 volts to allow the current to be adjust

sweet [91]

Answer:

600 and 1500 [ohm

Explanation:

To solve this problem we must use ohm's law, which tells us that the voltage is the product of the current by the resistance, so we have:

V = I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohm]

Therefore:

R = V/I

R1 = 60/(40*10^-3) = 1500 [ohm]

R2 = 60/(100*10^-3) = 600 [ohm]

So the resistance should be among 600 and 1500 [ohm]

4 0

3 years ago