<u>Slope-Intercept:</u>
y + 3 = 6(x + 2) - 3
y + 3 = 6x + 12 - 3
<u> -3 </u> <u> -3 </u>
y = 6x + 12
<u>Standard:</u>
y = 6x + 12
<u>-6x </u> <u>-6x </u>
-6x + y = 12
-1(-6x + y = 12)
6x - y = -12
<u>Graph:</u>
y = 6x + 12
↓ ↓
↓ y-intercept
slope
Start by graphing the y-intercept: (0, 12)
Then count the rise (up 6) and the run (right 1) from the y-intercept: (1, 18)
or
count the rise (down 6) and the run (left 1) from the y-intercept: (-1, 6)
Answer:
since M lies between point A and B , we came to know that,
M(4,6) =(x,y)
A(-2,-1)=(x1 ,y1)
B( _, _ )=(x2,y2)
Now using mid point formula,
x=x1×x2÷2 y=y1+y2÷2
so, point B is (10,13)
Answer:
Find the linearization L(x,y) of the function at each point. f(x,y) = x2 + y2 + 1 a. (4,0) b. (2,0) a. L(x,y) = Find the linearization L(x,y,z) of the function f(x,y,z) = 1x2 + y2 +z2 at the points (7,0,0), (3,4,0), and (4,4,7). The linearization of f(x,y,z) at (7,0,0) is L(x,y,z)= (Type an exact answer, using radicals as needed.)
So I will be assuming that EG = 8 is the length
of the line segment EG. If that's the case, therefore the coordinates of G would
simple be:
G =11 ± 8
G = 11 – 8, 11 + 8
G = 3, 19
<span>So G can have a coordinate of 3 or 19.</span>
