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Anit [1.1K]
3 years ago
13

According to the Bohr model of an atom, what happens when an electron moves from the second energy level to the third energy lev

el and then back to the second energy level? Energy is absorbed and then stored in the atom. Energy is released and then absorbed to form an absorption line. Energy is absorbed and then released to form an emission line. Energy is released from the atom, and the outer level is weakened.
Chemistry
2 answers:
kati45 [8]3 years ago
4 0
<span>Energy is absorbed and then released to form an emission line.

When electrons absorb energy they increase there energy level. This is only temporary and the excited electron then relaxes back down to its original energy level releasing energy.

The energy is released in form of EM radiation of a specific frequency depending on the element and how many energy levels the electron relaxes. 
This forms an emission line.</span><span />
Blababa [14]3 years ago
4 0

Answer:

C

Explanation:

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Amino acids are the basic parts of proteins
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Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0
oee [108]

Answer:

pH = 8.314

Explanation:

  • Y(OH)3(s) ↔ Y+  +  3OH-

equil:   S               S         3S

∴ Ksp = [ Y+ ] * [ OH- ]³ = 6.0 E-24

⇒ 6.0 E-24 = ( S )*( 3S )³

⇒ 6.0 E-24 = 27S∧4

⇒ 2.22 E-25 = S∧4

⇒ ( 2.22 E-25 )∧(1/4) = S

⇒ S = 6.866 E-7 M

⇒ [ OH- ] = 3*S =2.06 E-6 M

⇒ pOH = - Log [ OH- ]

⇒ pOH = - Log ( 2.06 E-6 )

⇒ pOH = 5.686

∴ pH = 14 - pOH

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8 0
3 years ago
An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 39 mg every 30 min. The IV bag
Korvikt [17]

Answer:

The Flow rate = 0.0208 mL/min

Explanation:

Data provided:

Rate of dose = 39 mg every 30 min = (39/30) mg/min  = 1.3 mg/min

also,

125mg of methylprednisolone is present in every 2 mL

thus,

concentration = (125/2) mg/mL = 62.5 mg/mL

Now,

The flow rate is given as:

Flow rate = Rate / Concentration

on substituting the respective values, we get

Flow rate = (1.3 mg/min) / (62.5mg/mL)

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3 0
3 years ago
4. Calculate the final concentration if water is added to 1.5 L of a 12 M
konstantin123 [22]

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

6 0
3 years ago
Based on what you’ve determined regarding one mole of sand and one mole of water, which statements must be correct? Select all t
Igoryamba

Answer:

-The mole is appropriate only for counting things that are very small.

-One mole is a very large number of something.

-A molecule of water is much smaller than a grain of sand.

Explanation:

8 0
2 years ago
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