<span>Hydrogen can be obtained economically as a byproduct in the electrolysis of "brine".
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A solution of sodium chloride (NaCl)and water (H2O) refers to the brine.The procedure of electrolysis includes utilizing an electric current to achieve a synthetic change and make new chemicals. The electrolysis of brine is a huge scale process used to make chlorine from salt, so three important chemicals, NaOH, Cl2, H2, can be gotten by electrolyzing brine.
Answer:
An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.
Explanation:
An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.
Answer:
pH of buffer =4.75
Explanation:
The pH of buffer solution is calculated using Henderson Hassalbalch's equation:
![pH=pKa+log[\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5B%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
Given:
pKa = 3.75
concentration of acid = concentration of formic acid = 1 M
concentration of salt = concentration of sodium formate = 10 M
![pH=3.75+log[\frac{10}{1}]=3.75+1=4.75](https://tex.z-dn.net/?f=pH%3D3.75%2Blog%5B%5Cfrac%7B10%7D%7B1%7D%5D%3D3.75%2B1%3D4.75)
pH of buffer =4.75
Answer:
The answer to your question is 6.0 moles of O₂
Explanation:
Data
2KClO₃ ⇒ 2KCl + 3O₂
moles of O₂ = ?
moles of KCl = 4
Process
To find the number of moles of O₂, use proportions and cross multiplication.
Use the coefficients of the balanced equation.
2 moles of KCl ----------------- 3 moles of O₂
4 moles of KCl ----------------- x
x = (4 x 3) / 2
-Simplification
x = 12/2
-Result
x = 6 moles of O₂
-Conclusion
When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.