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4 years ago

5

Assuming that the hill on the left will provide all of the potential energy for the ride, would this roller coaster actually mak

e it around the loop?
Thanks!

1 answer:

trapecia [35]4 years ago

3 0

Yes I believe it would I think the answer is D

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What is a metallic bond and how does it hold metals together?

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Answer:

Force that holds atoms together in a metallic substance.

Explanation:

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2 years ago

A magnet attracts more iron dusts at its end

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3 years ago

What average net force is required to stop a 3.5 kg bowling ball initially travelling at a speed of 1.5 m/s over a distance of 0

raketka [301]

First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is <u>-9,835 Newtons.</u>

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3 years ago

2. Kevin is a member of the school's track and field team. His favorite event is throwing the shot

Tju [1.3M]

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F=ma

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3 years ago

a particle of mass 1.3kg is sliding down a frictionless slope inclined at 30 to the horizontal. the acceleration of the particle

OverLord2011 [107]

Answer:

$4.9\ m/sec^2$

Explanation:

The computation of acceleration of the particle down the slope is shown below:-

data provided in the question

Particle of mass = 1.3 kg i,e sliding down

Inclined = 30 to the horizontal

based on the above information

Force is given by

$N = mg\ cos \theta$ ............ 1

and sliding force is given by

$F = mg\ sin\alpha$

$a = g(sin\ 30^{\circ})$

$= 9.8\times \frac{1}{2} m/sec^2$

= $= 4.9\ m/sec^2$

Hence, the acceleration of the particle down the slope is 4.9 m/sec^2

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3 years ago