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aniked [119]
4 years ago
14

The latent heat of fusion of alcohol is 25 kcal/kg and its melting point is -114 o C. It has a specific heat of 0.60 in its liqu

id state. Calculate the energy needed to melt 2.0 kg of solid alcohol at -114 o C and raise it to a temperature of -14 o C.
A) 70 kcal
B) 120 kcal
C) 170 kcal
D) 220 kcal
Physics
1 answer:
Elanso [62]4 years ago
4 0

Answer:

Total energy is 170 kJ

Explanation:

Given data:

latent heat of fusion of alcohol is 25 kcal/kg

melting point of alcohol is -114 degree c

specific heat us 0.60 k cal/kg degree c

energy need for 2 kg solid alcohol is

for Melting:

Energy Q is calculated as

Energy, Q = 25 \times 2.0 kg = 50 kJ

Energy required for Heating liquid:

Energy, ΔH = 2.0 kg \times 0.60 \times (100°C) = 120 kJ

Total  energy = (50 kJ + 120 kJ) = 170 kJ

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a spherical mirror is cut in half horizontally will an image be formed by the bottom half of the mirror how
monitta

Answer:

Explanation:

the spherical mirror can form an image even if it is cut in half horizontally , but the image formed may be blurred.

pls mark as brainliest if you find it helpful

7 0
3 years ago
A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i
attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
  • As per Newton's equation of motion, V= U+at
  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
  • So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

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4 0
2 years ago
If a wave has a frequency of 50 Hz and a wavelength of 3 meters, what is its Velocity? (Use
allochka39001 [22]

Answer:

the answer is 150m/s

Explanation:

v=λf

v=50*3

v=150m/s

4 0
3 years ago
A 1.0 m string with a 5 g stopper on the end is whirled in a vertical circle. The speed of the stopper is 8 m/s at the top of th
Andrew [12]

Answer:

Explanation:

A )

At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy

1/2 m V² = mg x 2r + 1/2 mv²

m is mass of stopper , V is velocity at the bottom , r is radius of the circular path which is length of the string , v is velocity at the top

1/2  V² = g x 2r + 1/2 v²

 V² = g x 4r +  v²

 V² = 9.8 x 4 +  8²

V² = 103.2

V = 10.16 m/s

B )

If T be the tension at the top

Net downward force

= mg + T . This force provides centripetal force for the circular motion

mg +T = mv² / r

T =   mv²/r -mg

= m ( v²/r - g )

= .005 ( 8²/1 -g )

= .005 x 54.2

= .27 N .

C ) At the bottom

Net force = T  - mg , T is tension at the bottom , V is velocity at bottom

T-mg = mV²/r

T = m ( V²/r +g )

= .005 ( 10.16²/1 +9.8)

= .005 x 113

= .56 N .

3 0
4 years ago
1. What are the units of area under the line/curve?<br> 2. Does the area have any meaning?
TiliK225 [7]

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

<h3>What is area under velocity - time graph?</h3>

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

Learn more about velocity time graph here: brainly.com/question/4710544

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6 0
2 years ago
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