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ZanzabumX [31]
3 years ago
13

If you increase the frequency of a sound wave four times what will happen to its speed

Physics
2 answers:
Anika [276]3 years ago
8 0

Answer: The correct answer is "the speed of the wave becomes four times".

Explanation:

The relation between the speed, frequency and the wavelength is as follows:

v=f\lambda

Here, v is the speed of the wave, f is the frequency and \lambda is the wavelength.

The speed of the sound wave is directly proportional to the frequency.

In the given problem, if the speed of the sound wave is increased four times then the speed of the sound becomes four times.

Therefore, the speed of the sound wave becomes four times.

Serggg [28]3 years ago
4 0
A  w a v e ' s   f r e q u e n c y   c a n   b e   m a t h e m a t i c a l l y   e x p r e s s e d   a s   f = v / λ,  w h e r e   v   i s   t h e   s p e e d   a n d   λ   i s   t h e   w a v e l e n g t h . W e   c a n   s e e   t h a t   f r e q u e n c y   a n d   s p e e d   a r e   d i r e c t l y   p r o p o r t i o n a l   to   e a c h   o t h e r ,  t h a t   m e a n s   w h e n    f r e q u e n c y   i s   i n c r e a s e d    f o u r   t i m e s,  t h e   s p e e d   w i l l   a l s o   i n c r e a s e   f o u r   t i m e s<span>.</span>
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Myopia

Explanation:

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3 years ago
In an Atwood's machine, one block has a mass of 602.0 g, and the other a mass of 717.0 g. The pulley, which is mounted in horizo
Wittaler [7]

Answer:

The acceleration of the both masses is 0.0244 m/s².

Explanation:

Given that,

Mass of one block = 602.0 g

Mass of other block = 717.0 g

Radius = 1.70 cm

Height = 60.6 cm

Time = 7.00 s

Suppose we find  the magnitude of the acceleration of the 602.0-g block

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Using equation of motion

s=ut+\dfrac{1}{2}at^2

Where, s = distance

t = time

a = acceleration

Put the value into the formula

60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2

a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}

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Hence, The acceleration of the both masses is 0.0244 m/s².

5 0
3 years ago
Indiana jones (83.5 kg) is running 3.75 m/s when he jumps in a stationary 312 kg mine cart. what is their joint velocity afterwa
Lubov Fominskaja [6]

Answer:

.7917 m/s

Explanation:

This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.

3 0
3 years ago
Rachel hits a golf ball into the air. What type of motion is the ball's path?
sladkih [1.3K]

Answer:

omg

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Explanation:

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