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ZanzabumX [31]
3 years ago
13

If you increase the frequency of a sound wave four times what will happen to its speed

Physics
2 answers:
Anika [276]3 years ago
8 0

Answer: The correct answer is "the speed of the wave becomes four times".

Explanation:

The relation between the speed, frequency and the wavelength is as follows:

v=f\lambda

Here, v is the speed of the wave, f is the frequency and \lambda is the wavelength.

The speed of the sound wave is directly proportional to the frequency.

In the given problem, if the speed of the sound wave is increased four times then the speed of the sound becomes four times.

Therefore, the speed of the sound wave becomes four times.

Serggg [28]3 years ago
4 0
A  w a v e ' s   f r e q u e n c y   c a n   b e   m a t h e m a t i c a l l y   e x p r e s s e d   a s   f = v / λ,  w h e r e   v   i s   t h e   s p e e d   a n d   λ   i s   t h e   w a v e l e n g t h . W e   c a n   s e e   t h a t   f r e q u e n c y   a n d   s p e e d   a r e   d i r e c t l y   p r o p o r t i o n a l   to   e a c h   o t h e r ,  t h a t   m e a n s   w h e n    f r e q u e n c y   i s   i n c r e a s e d    f o u r   t i m e s,  t h e   s p e e d   w i l l   a l s o   i n c r e a s e   f o u r   t i m e s<span>.</span>
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Dahasolnce [82]

Answer:

I=1.5\times10^{-28}W/m^2

Explanation:

The intensity is related to the power and surface area by I=\frac{P}{A}=\frac{P}{4\pi r^2}. We need to calculate the surface area of a sphere of radius r=4.3ly.

Since 4.3ly is the distance light travels in 4.3 years at 299792458m/s, we can obtain it in meters by doing:

r=vt=(299792458m/s)(4.3\times365\times24\times60\times60s)=4.1\times10^{16}m

So we have:

I=\frac{P}{4\pi r^2}=\frac{3.2\times10^6W}{4\pi (4.1\times10^{16}m)^2}=1.5\times10^{-28}W/m^2

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3 years ago
A sled starts off with an initial velocity of 8 m/s and slows down to 2 m/s after 3 seconds. What was its acceleration?
melomori [17]

Answer:

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Explanation:

3 0
2 years ago
Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is
anastassius [24]

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

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The car B has the velocity of 25 Km/hr.

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Let the velocity of cars A and B are denoted as v_{1} \ and\ v_{2}

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We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of  linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are v'_{1} \ and\ v'_{2}

Hence the final momentum of the system is-

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As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e      

                              p_{i} =p_{f}

                               m_{1} v_{1} +m_{2}v_{2} =m_{1} v'_{1} +m_{2} v'_{2}

Hence the option A  is right.

7 0
3 years ago
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RideAnS [48]

Answer:

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Stability helps adjust how much distance the person, or object, needs to be.
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3 years ago
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